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Theorem rr-spce 45463
Description: Prove an existential. (Contributed by Rohan Ridenour, 12-Aug-2023.)
Hypotheses
Ref Expression
rr-spce.1 ((𝜑 ∧ 𝑥 = 𝐴) → 𝜓)
rr-spce.2 (𝜑 → 𝐴 ∈ 𝑉)
Assertion
Ref Expression
rr-spce (𝜑 → ∃𝑥𝜓)
Distinct variable groups:   𝜑,𝑥   𝑥,𝐴
Allowed substitution hints:   𝜓(𝑥)   𝑉(𝑥)

Proof of Theorem rr-spce
StepHypRef Expression
1 rr-spce.2 . . . 4 (𝜑 → 𝐴 ∈ 𝑉)
21elexd 3477 . . 3 (𝜑 → 𝐴 ∈ V)
3 isset 3468 . . 3 (𝐴 ∈ V ↔ ∃𝑥 𝑥 = 𝐴)
42, 3sylib 221 . 2 (𝜑 → ∃𝑥 𝑥 = 𝐴)
5 rr-spce.1 . . . 4 ((𝜑 ∧ 𝑥 = 𝐴) → 𝜓)
65ex 418 . . 3 (𝜑 → (𝑥 = 𝐴 → 𝜓))
76eximdv 1952 . 2 (𝜑 → (∃𝑥 𝑥 = 𝐴 → ∃𝑥𝜓))
84, 7mpd 16 1 (𝜑 → ∃𝑥𝜓)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∧ wa 401   = wceq 1570  ∃wex 1812   ∈ wcel 2147  Vcvv 3454
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-v 3456
This theorem is used by:  grumnudlem  45530
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