Theorem sbor2 43265

Description: One direction of sbor 2339, using fewer axioms. Compare 19.33 1916. (Contributed by Steven Nguyen, 18-Aug-2023.)

Assertion

Ref	Expression
sbor2	⊢ (([𝑡 / 𝑥]𝜑 ∨ [𝑡 / 𝑥]𝜓) → [𝑡 / 𝑥](𝜑 ∨ 𝜓))

Proof of Theorem sbor2

Step	Hyp	Ref	Expression
1		orc 881	. . 3 ⊢ (𝜑 → (𝜑 ∨ 𝜓))
2	1	sbimi 2110	. 2 ⊢ ([𝑡 / 𝑥]𝜑 → [𝑡 / 𝑥](𝜑 ∨ 𝜓))
3		olc 882	. . 3 ⊢ (𝜓 → (𝜑 ∨ 𝜓))
4	3	sbimi 2110	. 2 ⊢ ([𝑡 / 𝑥]𝜓 → [𝑡 / 𝑥](𝜑 ∨ 𝜓))
5	2, 4	jaoi 871	1 ⊢ (([𝑡 / 𝑥]𝜑 ∨ [𝑡 / 𝑥]𝜓) → [𝑡 / 𝑥](𝜑 ∨ 𝜓))

This proof depends on syntax axioms:   → wi 4   ∨ wo 861  [wsb 2098

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1812  df-sb 2099

This theorem is used by: (None)