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Theorem compleqd 3245
 Description: Equality deduction for complement. (Contributed by SF, 11-Jan-2015.)
Hypothesis
Ref Expression
compleqd.1 (φA = B)
Assertion
Ref Expression
compleqd (φ → ∼ A = ∼ B)

Proof of Theorem compleqd
StepHypRef Expression
1 compleqd.1 . 2 (φA = B)
2 compleq 3243 . 2 (A = B → ∼ A = ∼ B)
31, 2syl 15 1 (φ → ∼ A = ∼ B)
 Colors of variables: wff setvar class Syntax hints:   → wi 4   = wceq 1642   ∼ ccompl 3205 This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334 This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2478  df-v 2861  df-nin 3211  df-compl 3212 This theorem is referenced by:  difeq1  3246  difeq2  3247  symdifeq1  3248  symdifeq2  3249  nnadjoin  4520
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