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Theorem nfun 3232
Description: Hypothesis builder for union. (Contributed by SF, 2-Jan-2018.)
Hypotheses
Ref Expression
nfbool.1 ⊢ ℲxA
nfbool.2 ⊢ ℲxB
Assertion
Ref Expression
nfun ⊢ Ⅎx(A ∪ B)

Proof of Theorem nfun
StepHypRef Expression
1 df-un 3215 . 2 ⊢ (A ∪ B) = ( ∼ A ⩃ ∼ B)
2 nfbool.1 . . . 4 ⊢ ℲxA
32nfcompl 3230 . . 3 ⊢ Ⅎx ∼ A
4 nfbool.2 . . . 4 ⊢ ℲxB
54nfcompl 3230 . . 3 ⊢ Ⅎx ∼ B
63, 5nfnin 3229 . 2 ⊢ Ⅎx( ∼ A ⩃ ∼ B)
71, 6nfcxfr 2487 1 ⊢ Ⅎx(A ∪ B)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  Ⅎwnfc 2477   ⩃ cnin 3205   ∼ ccompl 3206   ∪ cun 3208
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334
This proof depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2479  df-nin 3212  df-compl 3213  df-un 3215
This theorem is used by:  nfsymdif  3234  nfop  4605
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