Theorem reseq2d 4935

Description: Equality deduction for restrictions. (Contributed by Paul Chapman, 22-Jun-2011.)

Hypothesis

Ref	Expression
reseqd.1	⊢ (φ → A = B)

Assertion

Ref	Expression
reseq2d	⊢ (φ → (C ↾ A) = (C ↾ B))

Proof of Theorem reseq2d

Step	Hyp	Ref	Expression
1		reseqd.1	. 2 ⊢ (φ → A = B)
2		reseq2 4930	. 2 ⊢ (A = B → (C ↾ A) = (C ↾ B))
3	1, 2	syl 15	1 ⊢ (φ → (C ↾ A) = (C ↾ B))

Syntax hints:   → wi 4   = wceq 1642   ↾ cres 4775

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334

This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2479  df-v 2862  df-nin 3212  df-compl 3213  df-in 3214  df-opab 4624  df-xp 4785  df-res 4789

This theorem is referenced by:  reseq12d  4936  resabs1  4993  resima2  5008  f1orescnv  5302  f1ococnv2  5310  fnressn  5439  oprssov  5604