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Theorem reseq2 4929
 Description: Equality theorem for restrictions. (Contributed by set.mm contributors, 8-Aug-1994.)
Assertion
Ref Expression
reseq2 (A = B → (C A) = (C B))

Proof of Theorem reseq2
StepHypRef Expression
1 xpeq1 4798 . . 3 (A = B → (A × V) = (B × V))
21ineq2d 3457 . 2 (A = B → (C ∩ (A × V)) = (C ∩ (B × V)))
3 df-res 4788 . 2 (C A) = (C ∩ (A × V))
4 df-res 4788 . 2 (C B) = (C ∩ (B × V))
52, 3, 43eqtr4g 2410 1 (A = B → (C A) = (C B))
 Colors of variables: wff setvar class Syntax hints:   → wi 4   = wceq 1642  Vcvv 2859   ∩ cin 3208   × cxp 4770   ↾ cres 4774 This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334 This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2478  df-v 2861  df-nin 3211  df-compl 3212  df-in 3213  df-opab 4623  df-xp 4784  df-res 4788 This theorem is referenced by:  reseq2i  4931  reseq2d  4934  resdisj  5050  fressnfv  5439
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