Theorem rexrab2 3005

Description: Existential quantification over a class abstraction. (Contributed by Mario Carneiro, 3-Sep-2015.)

Hypothesis

Ref	Expression
ralab2.1	⊢ (x = y → (ψ ↔ χ))

Assertion

Ref	Expression
rexrab2	⊢ (∃x ∈ {y ∈ A ∣ φ}ψ ↔ ∃y ∈ A (φ ∧ χ))

Distinct variable groups:   x,y   x,A   χ,x   φ,x   ψ,y

Allowed substitution hints:   φ(y)   ψ(x)   χ(y)   A(y)

Proof of Theorem rexrab2

Step	Hyp	Ref	Expression
1		df-rab 2624	. . 3 ⊢ {y ∈ A ∣ φ} = {y ∣ (y ∈ A ∧ φ)}
2	1	rexeqi 2813	. 2 ⊢ (∃x ∈ {y ∈ A ∣ φ}ψ ↔ ∃x ∈ {y ∣ (y ∈ A ∧ φ)}ψ)
3		ralab2.1	. . 3 ⊢ (x = y → (ψ ↔ χ))
4	3	rexab2 3004	. 2 ⊢ (∃x ∈ {y ∣ (y ∈ A ∧ φ)}ψ ↔ ∃y((y ∈ A ∧ φ) ∧ χ))
5		anass 630	. . . 4 ⊢ (((y ∈ A ∧ φ) ∧ χ) ↔ (y ∈ A ∧ (φ ∧ χ)))
6	5	exbii 1582	. . 3 ⊢ (∃y((y ∈ A ∧ φ) ∧ χ) ↔ ∃y(y ∈ A ∧ (φ ∧ χ)))
7		df-rex 2621	. . 3 ⊢ (∃y ∈ A (φ ∧ χ) ↔ ∃y(y ∈ A ∧ (φ ∧ χ)))
8	6, 7	bitr4i 243	. 2 ⊢ (∃y((y ∈ A ∧ φ) ∧ χ) ↔ ∃y ∈ A (φ ∧ χ))
9	2, 4, 8	3bitri 262	1 ⊢ (∃x ∈ {y ∈ A ∣ φ}ψ ↔ ∃y ∈ A (φ ∧ χ))

Syntax hints:   → wi 4   ↔ wb 176   ∧ wa 358  ∃wex 1541   ∈ wcel 1710  {cab 2339  ∃wrex 2616  {crab 2619

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334

This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2479  df-rex 2621  df-rab 2624

This theorem is referenced by: (None)