Theorem wdid0id4 1115

Description: Show a quantum identity that follows from classical identity in a WDOL. (Contributed by NM, 5-Mar-2006.)

Hypothesis

Ref	Expression
wdid0id5.1	(a ≡0 b) = 1

Assertion

Ref	Expression
wdid0id4	(a ≡4 b) = 1

Proof of Theorem wdid0id4

Step	Hyp	Ref	Expression
1		df-id4 53	. 2 (a ≡4 b) = ((a⊥ ∪ b) ∩ (b⊥ ∪ (a ∩ b)))
2		df-id0 49	. . . . 5 (a ≡0 b) = ((a⊥ ∪ b) ∩ (b⊥ ∪ a))
3	2	ax-r1 35	. . . 4 ((a⊥ ∪ b) ∩ (b⊥ ∪ a)) = (a ≡0 b)
4		wdid0id5.1	. . . 4 (a ≡0 b) = 1
5	3, 4	ax-r2 36	. . 3 ((a⊥ ∪ b) ∩ (b⊥ ∪ a)) = 1
6		wddi3 1109	. . . . . 6 ((b⊥ ∪ (a ∩ b)) ≡ ((b⊥ ∪ a) ∩ (b⊥ ∪ b))) = 1
7		wa2 192	. . . . . . . 8 ((b⊥ ∪ b) ≡ (b ∪ b⊥ )) = 1
8	7	wlan 370	. . . . . . 7 (((b⊥ ∪ a) ∩ (b⊥ ∪ b)) ≡ ((b⊥ ∪ a) ∩ (b ∪ b⊥ ))) = 1
9		wa4 194	. . . . . . . 8 (((b⊥ ∪ a) ∪ (b ∪ b⊥ )) ≡ (b ∪ b⊥ )) = 1
10	9	wleoa 376	. . . . . . 7 (((b⊥ ∪ a) ∩ (b ∪ b⊥ )) ≡ (b⊥ ∪ a)) = 1
11	8, 10	wr2 371	. . . . . 6 (((b⊥ ∪ a) ∩ (b⊥ ∪ b)) ≡ (b⊥ ∪ a)) = 1
12	6, 11	wr2 371	. . . . 5 ((b⊥ ∪ (a ∩ b)) ≡ (b⊥ ∪ a)) = 1
13	12	wr1 197	. . . 4 ((b⊥ ∪ a) ≡ (b⊥ ∪ (a ∩ b))) = 1
14	13	wlan 370	. . 3 (((a⊥ ∪ b) ∩ (b⊥ ∪ a)) ≡ ((a⊥ ∪ b) ∩ (b⊥ ∪ (a ∩ b)))) = 1
15	5, 14	wwbmp 205	. 2 ((a⊥ ∪ b) ∩ (b⊥ ∪ (a ∩ b))) = 1
16	1, 15	ax-r2 36	1 (a ≡4 b) = 1

Syntax hints:   = wb 1  ^⊥ wn 4   ∪ wo 6   ∩ wa 7  1wt 8   ≡₀ wid0 17   ≡₄ wid4 21

This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-a3 32  ax-a4 33  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38  ax-wom 361  ax-wdol 1104

This theorem depends on definitions:  df-b 39  df-a 40  df-t 41  df-f 42  df-i1 44  df-i2 45  df-id0 49  df-id4 53  df-le 129  df-le1 130  df-le2 131  df-cmtr 134

This theorem is referenced by:  wddi-4  1121