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Mirrors > Home > MPE Home > Th. List > elsn2 | Structured version Visualization version GIF version |
Description: There is exactly one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 12-Jun-1994.) |
Ref | Expression |
---|---|
elsn2.1 | ⊢ 𝐵 ∈ V |
Ref | Expression |
---|---|
elsn2 | ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | elsn2.1 | . 2 ⊢ 𝐵 ∈ V | |
2 | elsn2g 4603 | . 2 ⊢ (𝐵 ∈ V → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | |
3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵) |
Colors of variables: wff setvar class |
Syntax hints: ↔ wb 208 = wceq 1537 ∈ wcel 2114 Vcvv 3494 {csn 4567 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1796 ax-4 1810 ax-5 1911 ax-6 1970 ax-7 2015 ax-8 2116 ax-9 2124 ax-10 2145 ax-11 2161 ax-12 2177 ax-ext 2793 |
This theorem depends on definitions: df-bi 209 df-an 399 df-or 844 df-tru 1540 df-ex 1781 df-nf 1785 df-sb 2070 df-clab 2800 df-cleq 2814 df-clel 2893 df-nfc 2963 df-sn 4568 |
This theorem is referenced by: fparlem1 7807 fparlem2 7808 el1o 8124 fin1a2lem11 9832 fin1a2lem12 9833 elnn0 11900 elxnn0 11970 elfzp1 12958 fsumss 15082 fprodss 15302 elhoma 17292 islpidl 20019 zrhrhmb 20658 rest0 21777 qustgphaus 22731 taylfval 24947 elch0 29031 atoml2i 30160 bj-eltag 34292 bj-rest10b 34383 dibopelvalN 38294 dibopelval2 38296 climrec 41904 |
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