Theorem 3jaoian 1300

Description: Disjunction of 3 antecedents (inference). (Contributed by NM, 14-Oct-2005.)

Hypotheses

Ref	Expression
3jaoian.1	|- ( ( ph /\ ps ) -> ch )
3jaoian.2	|- ( ( th /\ ps ) -> ch )
3jaoian.3	|- ( ( ta /\ ps ) -> ch )

Assertion

Ref	Expression
3jaoian	|- ( ( ( ph \/ th \/ ta ) /\ ps ) -> ch )

Proof of Theorem 3jaoian

Step	Hyp	Ref	Expression
1		3jaoian.1	. . . 4 |- ( ( ph /\ ps ) -> ch )
2	1	ex 114	. . 3 |- ( ph -> ( ps -> ch ) )
3		3jaoian.2	. . . 4 |- ( ( th /\ ps ) -> ch )
4	3	ex 114	. . 3 |- ( th -> ( ps -> ch ) )
5		3jaoian.3	. . . 4 |- ( ( ta /\ ps ) -> ch )
6	5	ex 114	. . 3 |- ( ta -> ( ps -> ch ) )
7	2, 4, 6	3jaoi 1298	. 2 |- ( ( ph \/ th \/ ta ) -> ( ps -> ch ) )
8	7	imp 123	1 |- ( ( ( ph \/ th \/ ta ) /\ ps ) -> ch )

Syntax hints:   -> wi 4   /\ wa 103   \/ w3o 972

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 704

This theorem depends on definitions:  df-bi 116  df-3or 974  df-3an 975

This theorem is referenced by:  xrltnsym  9750  xrlttr  9752  xltnegi  9792  xaddcom  9818  xnegdi  9825  qbtwnxr  10214