Theorem sbalv 2005

Description: Quantify with new variable inside substitution. (Contributed by NM, 18-Aug-1993.)

Hypothesis

Ref	Expression
sbalv.1	|- ( [ y / x ] ph <-> ps )

Assertion

Ref	Expression
sbalv	|- ( [ y / x ] A. z ph <-> A. z ps )

Distinct variable groups:   x, z   y, z

Allowed substitution hints:   ph( x, y, z)   ps( x, y, z)

Proof of Theorem sbalv

Step	Hyp	Ref	Expression
1		sbal 2000	. 2 |- ( [ y / x ] A. z ph <-> A. z [ y / x ] ph )
2		sbalv.1	. . 3 |- ( [ y / x ] ph <-> ps )
3	2	albii 1470	. 2 |- ( A. z [ y / x ] ph <-> A. z ps )
4	1, 3	bitri 184	1 |- ( [ y / x ] A. z ph <-> A. z ps )

Syntax hints:   <-> wb 105   A.wal 1351   [wsb 1762

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 709  ax-5 1447  ax-7 1448  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-8 1504  ax-10 1505  ax-11 1506  ax-i12 1507  ax-bndl 1509  ax-4 1510  ax-17 1526  ax-i9 1530  ax-ial 1534  ax-i5r 1535

This theorem depends on definitions:  df-bi 117  df-nf 1461  df-sb 1763

This theorem is referenced by:  sbmo  2085  sbabel  2346  peano2  4596