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Mirrors > Home > ILE Home > Th. List > sbrbif | Unicode version |
Description: Introduce right biconditional inside of a substitution. (Contributed by NM, 18-Aug-1993.) |
Ref | Expression |
---|---|
sbrbif.1 | |
sbrbif.2 |
Ref | Expression |
---|---|
sbrbif |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | sbrbif.2 | . . 3 | |
2 | 1 | sbrbis 1941 | . 2 |
3 | sbrbif.1 | . . . 4 | |
4 | 3 | sbh 1756 | . . 3 |
5 | 4 | bibi2i 226 | . 2 |
6 | 2, 5 | bitri 183 | 1 |
Colors of variables: wff set class |
Syntax hints: wi 4 wb 104 wal 1333 wsb 1742 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 ax-io 699 ax-5 1427 ax-7 1428 ax-gen 1429 ax-ie1 1473 ax-ie2 1474 ax-8 1484 ax-10 1485 ax-11 1486 ax-i12 1487 ax-4 1490 ax-17 1506 ax-i9 1510 ax-ial 1514 ax-i5r 1515 |
This theorem depends on definitions: df-bi 116 df-nf 1441 df-sb 1743 |
This theorem is referenced by: (None) |
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