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Mirrors > Home > ILE Home > Th. List > fneq2i | GIF version |
Description: Equality inference for function predicate with domain. (Contributed by NM, 4-Sep-2011.) |
Ref | Expression |
---|---|
fneq2i.1 | ⊢ 𝐴 = 𝐵 |
Ref | Expression |
---|---|
fneq2i | ⊢ (𝐹 Fn 𝐴 ↔ 𝐹 Fn 𝐵) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | fneq2i.1 | . 2 ⊢ 𝐴 = 𝐵 | |
2 | fneq2 5317 | . 2 ⊢ (𝐴 = 𝐵 → (𝐹 Fn 𝐴 ↔ 𝐹 Fn 𝐵)) | |
3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐹 Fn 𝐴 ↔ 𝐹 Fn 𝐵) |
Colors of variables: wff set class |
Syntax hints: ↔ wb 105 = wceq 1363 Fn wfn 5223 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1457 ax-gen 1459 ax-4 1520 ax-17 1536 ax-ext 2169 |
This theorem depends on definitions: df-bi 117 df-cleq 2180 df-fn 5231 |
This theorem is referenced by: fnunsn 5335 tpos0 6289 dfixp 6714 ser0f 10529 fnpr2o 12777 |
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