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Theorem nesym 2409
Description: Characterization of inequality in terms of reversed equality (see bicom 140). (Contributed by BJ, 7-Jul-2018.)
Assertion
Ref Expression
nesym (𝐴𝐵 ↔ ¬ 𝐵 = 𝐴)

Proof of Theorem nesym
StepHypRef Expression
1 eqcom 2195 . 2 (𝐴 = 𝐵𝐵 = 𝐴)
21necon3abii 2400 1 (𝐴𝐵 ↔ ¬ 𝐵 = 𝐴)
Colors of variables: wff set class
Syntax hints:  ¬ wn 3  wb 105   = wceq 1364  wne 2364
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-5 1458  ax-gen 1460  ax-ext 2175
This theorem depends on definitions:  df-bi 117  df-cleq 2186  df-ne 2365
This theorem is referenced by:  nesymi  2410  nesymir  2411  0neqopab  5963  fzdifsuc  10147  isprm3  12256
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