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Theorem nf2 1655
Description: An alternate definition of df-nf 1448, which does not involve nested quantifiers on the same variable. (Contributed by Mario Carneiro, 24-Sep-2016.)
Assertion
Ref Expression
nf2 (Ⅎ𝑥𝜑 ↔ (∃𝑥𝜑 → ∀𝑥𝜑))

Proof of Theorem nf2
StepHypRef Expression
1 df-nf 1448 . 2 (Ⅎ𝑥𝜑 ↔ ∀𝑥(𝜑 → ∀𝑥𝜑))
2 nfa1 1528 . . . 4 𝑥𝑥𝜑
32nfri 1506 . . 3 (∀𝑥𝜑 → ∀𝑥𝑥𝜑)
4319.23h 1485 . 2 (∀𝑥(𝜑 → ∀𝑥𝜑) ↔ (∃𝑥𝜑 → ∀𝑥𝜑))
51, 4bitri 183 1 (Ⅎ𝑥𝜑 ↔ (∃𝑥𝜑 → ∀𝑥𝜑))
Colors of variables: wff set class
Syntax hints:  wi 4  wb 104  wal 1340  wnf 1447  wex 1479
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-gen 1436  ax-ie2 1481  ax-4 1497  ax-ial 1521
This theorem depends on definitions:  df-bi 116  df-nf 1448
This theorem is referenced by:  nf3  1656  nf4dc  1657  nf4r  1658  nfd2  2009  eusv2i  4427
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