Theorem simplbda 384

Description: Deduction eliminating a conjunct. (Contributed by NM, 22-Oct-2007.)

Hypothesis

Ref	Expression
pm3.26bda.1	⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃)))

Assertion

Ref	Expression
simplbda	⊢ ((𝜑 ∧ 𝜓) → 𝜃)

Proof of Theorem simplbda

Step	Hyp	Ref	Expression
1		pm3.26bda.1	. . 3 ⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃)))
2	1	biimpa 296	. 2 ⊢ ((𝜑 ∧ 𝜓) → (𝜒 ∧ 𝜃))
3	2	simprd 114	1 ⊢ ((𝜑 ∧ 𝜓) → 𝜃)

This proof depends on syntax axioms:   → wi 4   ∧ wa 104   ↔ wb 105

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107

This proof depends on definitions:  df-bi 117

This theorem is used by:  suppcofn  6506  cntzi  14156  rhmpropd  14653  lsslmod  14808  tgcl  15264  cldopn  15307  cncnp  15430  blgt0  15602  xblss2ps  15604  xblss2  15605  mopni  15682  metrest  15706  dvcl  15883  dvcnp2cntop  15899