Theorem simplbda 382

Description: Deduction eliminating a conjunct. (Contributed by NM, 22-Oct-2007.)

Hypothesis

Ref	Expression
pm3.26bda.1	⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃)))

Assertion

Ref	Expression
simplbda	⊢ ((𝜑 ∧ 𝜓) → 𝜃)

Proof of Theorem simplbda

Step	Hyp	Ref	Expression
1		pm3.26bda.1	. . 3 ⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃)))
2	1	biimpa 294	. 2 ⊢ ((𝜑 ∧ 𝜓) → (𝜒 ∧ 𝜃))
3	2	simprd 113	1 ⊢ ((𝜑 ∧ 𝜓) → 𝜃)

Syntax hints:   → wi 4   ∧ wa 103   ↔ wb 104

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106

This theorem depends on definitions:  df-bi 116

This theorem is referenced by:  tgcl  12704  cldopn  12747  cncnp  12870  blgt0  13042  xblss2ps  13044  xblss2  13045  mopni  13122  metrest  13146  dvcl  13292  dvcnp2cntop  13303