Theorem 3orel3 1495

Description: Partial elimination of a triple disjunction by denial of a disjunct. (Contributed by Scott Fenton, 26-Mar-2011.)

Assertion

Ref	Expression
3orel3	⊢ (¬ 𝜒 → ((𝜑 ∨ 𝜓 ∨ 𝜒) → (𝜑 ∨ 𝜓)))

Proof of Theorem 3orel3

Step	Hyp	Ref	Expression
1		df-3or 1094	. 2 ⊢ ((𝜑 ∨ 𝜓 ∨ 𝜒) ↔ ((𝜑 ∨ 𝜓) ∨ 𝜒))
2		orel2 897	. 2 ⊢ (¬ 𝜒 → (((𝜑 ∨ 𝜓) ∨ 𝜒) → (𝜑 ∨ 𝜓)))
3	1, 2	biimtrid 244	1 ⊢ (¬ 𝜒 → ((𝜑 ∨ 𝜓 ∨ 𝜒) → (𝜑 ∨ 𝜓)))

Syntax hints:  ¬ wn 3   → wi 4   ∨ wo 854   ∨ w3o 1092

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 209  df-or 855  df-3or 1094

This theorem is referenced by:  3orel13  1496  ttrcltr  9632  nolesgn2o  27657  nosep2o  27668  noinfbnd1lem5  27713  noinfbnd2lem1  27716