| Metamath Proof Explorer |
< Previous
Next >
Nearby theorems |
||
| Mirrors > Home > MPE Home > Th. List > abanssr | Structured version Visualization version GIF version | ||
| Description: A class abstraction with a conjunction is a subset of the class abstraction with the right conjunct only. (Contributed by AV, 7-Aug-2024.) (Proof shortened by SN, 22-Aug-2024.) |
| Ref | Expression |
|---|---|
| abanssr | ⊢ {𝑥 ∣ (𝜑 ∧ 𝜓)} ⊆ {𝑥 ∣ 𝜓} |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | simpr 489 | . 2 ⊢ ((𝜑 ∧ 𝜓) → 𝜓) | |
| 2 | 1 | ss2abi 4028 | 1 ⊢ {𝑥 ∣ (𝜑 ∧ 𝜓)} ⊆ {𝑥 ∣ 𝜓} |
| Colors of variables: wff setvar class |
| Syntax hints: ∧ wa 400 {cab 2748 ⊆ wss 3913 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1823 ax-4 1837 ax-5 1938 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-tru 1571 df-sb 2099 df-clab 2749 df-ss 3930 |
| This theorem is referenced by: hashf1lem1 14495 |
| Copyright terms: Public domain | W3C validator |