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Theorem abanssr 4257
Description: A class abstraction with a conjunction is a subset of the class abstraction with the right conjunct only. (Contributed by AV, 7-Aug-2024.) (Proof shortened by SN, 22-Aug-2024.)
Assertion
Ref Expression
abanssr {𝑥 ∣ (𝜑 ∧ 𝜓)} ⊆ {𝑥 ∣ 𝜓}

Proof of Theorem abanssr
StepHypRef Expression
1 simpr 490 . 2 ((𝜑 ∧ 𝜓) → 𝜓)
21ss2abi 3991 1 {𝑥 ∣ (𝜑 ∧ 𝜓)} ⊆ {𝑥 ∣ 𝜓}
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ∧ wa 401  {cab 2738   ⊆ wss 3895
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1572  df-ex 1812  df-sb 2099  df-clab 2739  df-ss 3896
This theorem is used by:  hashf1lem1  14600
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