Theorem bj-equsvt 37595

Description: A variant of equsv 2036. (Contributed by BJ, 7-Oct-2024.)

Assertion

Ref	Expression
bj-equsvt	⊢ (Ⅎ'𝑥𝜑 → (∀𝑥(𝑥 = 𝑦 → 𝜑) ↔ 𝜑))

Distinct variable group:   𝑥,𝑦

Allowed substitution hints:   𝜑(𝑥, 𝑦)

Proof of Theorem bj-equsvt

Step	Hyp	Ref	Expression
1		bj-19.23t 37586	. 2 ⊢ (Ⅎ'𝑥𝜑 → (∀𝑥(𝑥 = 𝑦 → 𝜑) ↔ (∃𝑥 𝑥 = 𝑦 → 𝜑)))
2		ax6ev 2002	. . 3 ⊢ ∃𝑥 𝑥 = 𝑦
3	2	a1bi 365	. 2 ⊢ (𝜑 ↔ (∃𝑥 𝑥 = 𝑦 → 𝜑))
4	1, 3	bitr4di 292	1 ⊢ (Ⅎ'𝑥𝜑 → (∀𝑥(𝑥 = 𝑦 → 𝜑) ↔ 𝜑))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209  ∀wal 1568  ∃wex 1812  Ⅎ'wnnf 37550

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-6 2000

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-bj-nnf 37551

This theorem is used by:  bj-equsalvwd  37596