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| Mirrors > Home > MPE Home > Th. List > cadifp | Structured version Visualization version GIF version | ||
| Description: The value of the carry is, if the input carry is true, the disjunction, and if the input carry is false, the conjunction, of the other two inputs. (Contributed by BJ, 8-Oct-2019.) |
| Ref | Expression |
|---|---|
| cadifp | ⊢ (cadd(𝜑, 𝜓, 𝜒) ↔ if-(𝜒, (𝜑 ∨ 𝜓), (𝜑 ∧ 𝜓))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cad1 1646 | . 2 ⊢ (𝜒 → (cadd(𝜑, 𝜓, 𝜒) ↔ (𝜑 ∨ 𝜓))) | |
| 2 | cad0 1647 | . 2 ⊢ (¬ 𝜒 → (cadd(𝜑, 𝜓, 𝜒) ↔ (𝜑 ∧ 𝜓))) | |
| 3 | 1, 2 | casesifp 1093 | 1 ⊢ (cadd(𝜑, 𝜓, 𝜒) ↔ if-(𝜒, (𝜑 ∨ 𝜓), (𝜑 ∧ 𝜓))) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: ↔ wb 209 ∧ wa 400 ∨ wo 860 if-wif 1077 caddwcad 1635 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 |
| This proof depends on definitions: df-bi 210 df-an 401 df-or 861 df-ifp 1078 df-3or 1103 df-3an 1104 df-xor 1541 df-cad 1636 |
| This theorem is used by: wl-df-3mintru2 38158 |
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