Theorem contrd 36255

Description: A proof by contradiction, in deduction form. (Contributed by Giovanni Mascellani, 19-Mar-2018.)

Hypotheses

Ref	Expression
contrd.1	⊢ (𝜑 → (¬ 𝜓 → 𝜒))
contrd.2	⊢ (𝜑 → (¬ 𝜓 → ¬ 𝜒))

Assertion

Ref	Expression
contrd	⊢ (𝜑 → 𝜓)

Proof of Theorem contrd

Step	Hyp	Ref	Expression
1		contrd.1	. . 3 ⊢ (𝜑 → (¬ 𝜓 → 𝜒))
2		contrd.2	. . 3 ⊢ (𝜑 → (¬ 𝜓 → ¬ 𝜒))
3	1, 2	jcad 513	. 2 ⊢ (𝜑 → (¬ 𝜓 → (𝜒 ∧ ¬ 𝜒)))
4		pm2.24 124	. . . . 5 ⊢ (𝜒 → (¬ 𝜒 → 𝜓))
5	4	imp 407	. . . 4 ⊢ ((𝜒 ∧ ¬ 𝜒) → 𝜓)
6	5	imim2i 16	. . 3 ⊢ ((¬ 𝜓 → (𝜒 ∧ ¬ 𝜒)) → (¬ 𝜓 → 𝜓))
7	6	pm2.18d 127	. 2 ⊢ ((¬ 𝜓 → (𝜒 ∧ ¬ 𝜒)) → 𝜓)
8	3, 7	syl 17	1 ⊢ (𝜑 → 𝜓)

Syntax hints:  ¬ wn 3   → wi 4   ∧ wa 396

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 206  df-an 397

This theorem is referenced by:  mpobi123f  36320  mptbi12f  36324  ac6s6  36330