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Theorem elabgw 3692
Description: Membership in a class abstraction, using two substitution hypotheses to avoid a disjoint variable condition on 𝑥 and 𝐴. This is to elabg 3690 what sbievw2 2098 is to sbievw 2093. (Contributed by SN, 20-Apr-2024.)
Hypotheses
Ref Expression
elabgw.1 (𝑥 = 𝑦 → (𝜑𝜓))
elabgw.2 (𝑦 = 𝐴 → (𝜓𝜒))
Assertion
Ref Expression
elabgw (𝐴𝑉 → (𝐴 ∈ {𝑥𝜑} ↔ 𝜒))
Distinct variable groups:   𝑦,𝐴   𝑥,𝑦   𝜑,𝑦   𝜒,𝑦   𝜓,𝑥
Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑦)   𝜒(𝑥)   𝐴(𝑥)   𝑉(𝑥,𝑦)

Proof of Theorem elabgw
StepHypRef Expression
1 eleq1 2832 . 2 (𝑦 = 𝐴 → (𝑦 ∈ {𝑥𝜑} ↔ 𝐴 ∈ {𝑥𝜑}))
2 elabgw.2 . 2 (𝑦 = 𝐴 → (𝜓𝜒))
3 df-clab 2718 . . 3 (𝑦 ∈ {𝑥𝜑} ↔ [𝑦 / 𝑥]𝜑)
4 elabgw.1 . . . 4 (𝑥 = 𝑦 → (𝜑𝜓))
54sbievw 2093 . . 3 ([𝑦 / 𝑥]𝜑𝜓)
63, 5bitri 275 . 2 (𝑦 ∈ {𝑥𝜑} ↔ 𝜓)
71, 2, 6vtoclbg 3569 1 (𝐴𝑉 → (𝐴 ∈ {𝑥𝜑} ↔ 𝜒))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206   = wceq 1537  [wsb 2064  wcel 2108  {cab 2717
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1793  ax-4 1807  ax-5 1909  ax-6 1967  ax-7 2007  ax-8 2110  ax-9 2118  ax-ext 2711
This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1540  df-ex 1778  df-sb 2065  df-clab 2718  df-cleq 2732  df-clel 2819
This theorem is referenced by:  elab2gw  3693
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