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Theorem sbievw2 2137
Description: sbievw 2133 applied twice, avoiding a DV condition on 𝑥, 𝑦. Based on proofs by Wolf Lammen. (Contributed by Steven Nguyen, 29-Jul-2023.)
Hypotheses
Ref Expression
sbievw2.1 (𝑥 = 𝑤 → (𝜑 ↔ 𝜒))
sbievw2.2 (𝑤 = 𝑦 → (𝜒 ↔ 𝜓))
Assertion
Ref Expression
sbievw2 ([𝑦 / 𝑥]𝜑 ↔ 𝜓)
Distinct variable groups:   𝑥,𝑤   𝑦,𝑤   𝜑,𝑤   𝜓,𝑤   𝜒,𝑥
Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝜓(𝑥, 𝑦)   𝜒(𝑦, 𝑤)

Proof of Theorem sbievw2
StepHypRef Expression
1 sbcom3vv 2136 . . 3 ([𝑦 / 𝑤][𝑤 / 𝑥]𝜑 ↔ [𝑦 / 𝑤][𝑦 / 𝑥]𝜑)
2 sbievw2.1 . . . . 5 (𝑥 = 𝑤 → (𝜑 ↔ 𝜒))
32sbievw 2133 . . . 4 ([𝑤 / 𝑥]𝜑 ↔ 𝜒)
43sbbii 2115 . . 3 ([𝑦 / 𝑤][𝑤 / 𝑥]𝜑 ↔ [𝑦 / 𝑤]𝜒)
5 sbv 2127 . . 3 ([𝑦 / 𝑤][𝑦 / 𝑥]𝜑 ↔ [𝑦 / 𝑥]𝜑)
61, 4, 53bitr3i 304 . 2 ([𝑦 / 𝑤]𝜒 ↔ [𝑦 / 𝑥]𝜑)
7 sbievw2.2 . . 3 (𝑤 = 𝑦 → (𝜒 ↔ 𝜓))
87sbievw 2133 . 2 ([𝑦 / 𝑤]𝜒 ↔ 𝜓)
96, 8bitr3i 280 1 ([𝑦 / 𝑥]𝜑 ↔ 𝜓)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209  [wsb 2101
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-sb 2102
This theorem is used by:  sbco2vv  2138  equsb3  2142  equsb3r  2143  elsb1  2155  elsb2  2164  eqsb1  2890  clelsb1  2891  clelsb2  2892  sbss  4479
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