Theorem sbievw 2099

Description: Conversion of implicit substitution to explicit substitution. Version of sbie 2506 and sbiev 2319 with more disjoint variable conditions, requiring fewer axioms. (Contributed by NM, 30-Jun-1994.) (Revised by BJ, 18-Jul-2023.) (Proof shortened by SN, 24-Aug-2025.)

Hypothesis

Ref	Expression
sbievw.is	⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓))

Assertion

Ref	Expression
sbievw	⊢ ([𝑦 / 𝑥]𝜑 ↔ 𝜓)

Distinct variable groups:   𝑥,𝑦   𝜓,𝑥

Allowed substitution hints:   𝜑(𝑥,𝑦)   𝜓(𝑦)

Proof of Theorem sbievw

Step	Hyp	Ref	Expression
1		sbievw.is	. . 3 ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓))
2	1	sbbiiev 2098	. 2 ⊢ ([𝑦 / 𝑥]𝜑 ↔ [𝑦 / 𝑥]𝜓)
3		sbv 2094	. 2 ⊢ ([𝑦 / 𝑥]𝜓 ↔ 𝜓)
4	2, 3	bitri 275	1 ⊢ ([𝑦 / 𝑥]𝜑 ↔ 𝜓)

Syntax hints:   → wi 4   ↔ wb 206  [wsb 2068

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010

This theorem depends on definitions:  df-bi 207  df-an 396  df-ex 1782  df-sb 2069

This theorem is referenced by:  sbiedvw  2101  2sbievw  2102  sbievw2  2104  cbvsbv  2106  sbco4  2108  sbid2vw  2267  2mosOLD  2650  eqabbw  2809  sbralie  3315  sbralieALT  3316  rabrabi  3408  elabgw  3620  ralab  3639  sbcco2  3755  sbcie2g  3769  csbied  3873  dfss2  3907  unabw  4247  notabw  4253  2reu8i  47561  ichcircshi  47914