Theorem elimne0 11125

Description: Hypothesis for weak deduction theorem to eliminate 𝐴 ≠ 0. (Contributed by NM, 15-May-1999.)

Assertion

Ref	Expression
elimne0	⊢ if(𝐴 ≠ 0, 𝐴, 1) ≠ 0

Proof of Theorem elimne0

Step	Hyp	Ref	Expression
1		neeq1 2996	. 2 ⊢ (𝐴 = if(𝐴 ≠ 0, 𝐴, 1) → (𝐴 ≠ 0 ↔ if(𝐴 ≠ 0, 𝐴, 1) ≠ 0))
2		neeq1 2996	. 2 ⊢ (1 = if(𝐴 ≠ 0, 𝐴, 1) → (1 ≠ 0 ↔ if(𝐴 ≠ 0, 𝐴, 1) ≠ 0))
3		ax-1ne0 11098	. 2 ⊢ 1 ≠ 0
4	1, 2, 3	elimhyp 4520	1 ⊢ if(𝐴 ≠ 0, 𝐴, 1) ≠ 0

Syntax hints:   ≠ wne 2934  ifcif 4454  0cc0 11029  1c1 11030

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-8 2121  ax-9 2129  ax-ext 2711  ax-1ne0 11098

This theorem depends on definitions:  df-bi 208  df-an 397  df-or 854  df-ex 1787  df-sb 2074  df-clab 2718  df-cleq 2731  df-clel 2814  df-ne 2935  df-if 4455

This theorem is referenced by:  sqdivzi  35956