Theorem exisym1 36407

Description: A symmetry with ∃.

See negsym1 36400 for more information. (Contributed by Anthony Hart, 4-Sep-2011.)

Assertion

Ref	Expression
exisym1	⊢ (∃𝑥∃𝑥⊥ → ∃𝑥𝜑)

Proof of Theorem exisym1

Step	Hyp	Ref	Expression
1		nfe1 2148	. 2 ⊢ Ⅎ𝑥∃𝑥𝜑
2		falim 1554	. . 3 ⊢ (⊥ → 𝜑)
3	2	eximi 1832	. 2 ⊢ (∃𝑥⊥ → ∃𝑥𝜑)
4	1, 3	exlimi 2215	1 ⊢ (∃𝑥∃𝑥⊥ → ∃𝑥𝜑)

Syntax hints:   → wi 4  ⊥wfal 1549  ∃wex 1776

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1792  ax-4 1806  ax-5 1908  ax-6 1965  ax-7 2005  ax-10 2139  ax-12 2175

This theorem depends on definitions:  df-bi 207  df-tru 1540  df-fal 1550  df-ex 1777  df-nf 1781

This theorem is referenced by: (None)