Theorem ifpdfbi 1076

Description: Define the biconditional as conditional logic operator. (Contributed by RP, 20-Apr-2020.) (Proof shortened by Wolf Lammen, 30-Apr-2024.)

Assertion

Ref	Expression
ifpdfbi	⊢ ((𝜑 ↔ 𝜓) ↔ if-(𝜑, 𝜓, ¬ 𝜓))

Proof of Theorem ifpdfbi

Step	Hyp	Ref	Expression
1		con34b 317	. . 3 ⊢ ((𝜓 → 𝜑) ↔ (¬ 𝜑 → ¬ 𝜓))
2	1	anbi2i 629	. 2 ⊢ (((𝜑 → 𝜓) ∧ (𝜓 → 𝜑)) ↔ ((𝜑 → 𝜓) ∧ (¬ 𝜑 → ¬ 𝜓)))
3		dfbi2 475	. 2 ⊢ ((𝜑 ↔ 𝜓) ↔ ((𝜑 → 𝜓) ∧ (𝜓 → 𝜑)))
4		dfifp2 1070	. 2 ⊢ (if-(𝜑, 𝜓, ¬ 𝜓) ↔ ((𝜑 → 𝜓) ∧ (¬ 𝜑 → ¬ 𝜓)))
5	2, 3, 4	3bitr4i 304	1 ⊢ ((𝜑 ↔ 𝜓) ↔ if-(𝜑, 𝜓, ¬ 𝜓))

Syntax hints:  ¬ wn 3   → wi 4   ↔ wb 207   ∧ wa 396  if-wif 1068

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 208  df-an 397  df-or 854  df-ifp 1069

This theorem is referenced by:  wl-df3xor2  37838  wl-2xor  37852  ifpbiidcor  43925  ifpbicor  43926