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Theorem imdistan 571
Description: Distribution of implication with conjunction. (Contributed by NM, 31-May-1999.) (Proof shortened by Wolf Lammen, 6-Dec-2012.)
Assertion
Ref Expression
imdistan ((𝜑 → (𝜓𝜒)) ↔ ((𝜑𝜓) → (𝜑𝜒)))

Proof of Theorem imdistan
StepHypRef Expression
1 pm5.42 547 . 2 ((𝜑 → (𝜓𝜒)) ↔ (𝜑 → (𝜓 → (𝜑𝜒))))
2 impexp 454 . 2 (((𝜑𝜓) → (𝜑𝜒)) ↔ (𝜑 → (𝜓 → (𝜑𝜒))))
31, 2bitr4i 281 1 ((𝜑 → (𝜓𝜒)) ↔ ((𝜑𝜓) → (𝜑𝜒)))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 209  wa 399
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 210  df-an 400
This theorem is referenced by:  imdistand  574  rmoim  3706  ss2rab  4022  marypha2lem3  8889  inxpss3  35689
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