P. 6 of Theorem List - Metamath Proof Explorer

Theorem List for Metamath Proof Explorer - 501-600   *Has distinct variable group(s)

Type	Label	Description
Statement
Theorem	simprd 501	Deduction eliminating a conjunct. (Contributed by NM, 14-May-1993.) A translation of natural deduction rule ∧ ER (∧ elimination right), see natded 30769. (Proof shortened by Wolf Lammen, 3-Oct-2013.)
⊢ (𝜑 → (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜑 → 𝜒)
Theorem	simplbi 502	Deduction eliminating a conjunct. (Contributed by NM, 27-May-1998.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜑 → 𝜓)
Theorem	simprbi 503	Deduction eliminating a conjunct. (Contributed by NM, 27-May-1998.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜑 → 𝜒)
Theorem	simprbda 504	Deduction eliminating a conjunct. (Contributed by NM, 22-Oct-2007.)
⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃)))    ⇒   ⊢ ((𝜑 ∧ 𝜓) → 𝜒)
Theorem	simplbda 505	Deduction eliminating a conjunct. (Contributed by NM, 22-Oct-2007.)
⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃)))    ⇒   ⊢ ((𝜑 ∧ 𝜓) → 𝜃)
Theorem	simplbi2 506	Deduction eliminating a conjunct. (Contributed by Alan Sare, 31-Dec-2011.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜓 → (𝜒 → 𝜑))
Theorem	simplbi2comt 507	Closed form of simplbi2com 508. (Contributed by Alan Sare, 22-Jul-2012.)
⊢ ((𝜑 ↔ (𝜓 ∧ 𝜒)) → (𝜒 → (𝜓 → 𝜑)))
Theorem	simplbi2com 508	A deduction eliminating a conjunct, similar to simplbi2 506. (Contributed by Alan Sare, 22-Jul-2012.) (Proof shortened by Wolf Lammen, 10-Nov-2012.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜒 → (𝜓 → 𝜑))
Theorem	birani 509	Inference adding a conjunct to the left-hand side of a biconditional. (Contributed by Matthew House, 22-May-2026.)
⊢ (𝜑 ↔ 𝜓)    ⇒   ⊢ ((𝜑 ∧ 𝜒) → 𝜓)
Theorem	bilani 510	Inference adding a conjunct to the left-hand side of a biconditional. (Contributed by Matthew House, 22-May-2026.)
⊢ (𝜑 ↔ 𝜓)    ⇒   ⊢ ((𝜒 ∧ 𝜑) → 𝜓)
Theorem	biranri 511	Inference adding a conjunct to the right-hand side of a biconditional. (Contributed by Matthew House, 22-May-2026.)
⊢ (𝜑 ↔ 𝜓)    ⇒   ⊢ ((𝜓 ∧ 𝜒) → 𝜑)
Theorem	bilanri 512	Inference adding a conjunct to the right-hand side of a biconditional. (Contributed by Matthew House, 22-May-2026.)
⊢ (𝜑 ↔ 𝜓)    ⇒   ⊢ ((𝜒 ∧ 𝜓) → 𝜑)
Theorem	simpl2im 513	Implication from an eliminated conjunct implied by the antecedent. (Contributed by BJ/AV, 5-Apr-2021.) (Proof shortened by Wolf Lammen, 26-Mar-2022.)
⊢ (𝜑 → (𝜓 ∧ 𝜒))    &   ⊢ (𝜒 → 𝜃)    ⇒   ⊢ (𝜑 → 𝜃)
Theorem	simplbiim 514	Implication from an eliminated conjunct equivalent to the antecedent. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) (Proof shortened by Wolf Lammen, 26-Mar-2022.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    &   ⊢ (𝜒 → 𝜃)    ⇒   ⊢ (𝜑 → 𝜃)
Theorem	impel 515	An inference for implication elimination. (Contributed by Giovanni Mascellani, 23-May-2019.) (Proof shortened by Wolf Lammen, 2-Sep-2020.)
⊢ (𝜑 → (𝜓 → 𝜒))    &   ⊢ (𝜃 → 𝜓)    ⇒   ⊢ ((𝜑 ∧ 𝜃) → 𝜒)
Theorem	mpan9 516	Modus ponens conjoining dissimilar antecedents. (Contributed by NM, 1-Feb-2008.) (Proof shortened by Andrew Salmon, 7-May-2011.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜒 → (𝜓 → 𝜃))    ⇒   ⊢ ((𝜑 ∧ 𝜒) → 𝜃)
Theorem	sylan9 517	Nested syllogism inference conjoining dissimilar antecedents. (Contributed by NM, 14-May-1993.) (Proof shortened by Andrew Salmon, 7-May-2011.)
⊢ (𝜑 → (𝜓 → 𝜒))    &   ⊢ (𝜃 → (𝜒 → 𝜏))    ⇒   ⊢ ((𝜑 ∧ 𝜃) → (𝜓 → 𝜏))
Theorem	sylan9r 518	Nested syllogism inference conjoining dissimilar antecedents. (Contributed by NM, 14-May-1993.)
⊢ (𝜑 → (𝜓 → 𝜒))    &   ⊢ (𝜃 → (𝜒 → 𝜏))    ⇒   ⊢ ((𝜃 ∧ 𝜑) → (𝜓 → 𝜏))
Theorem	sylan9bb 519	Nested syllogism inference conjoining dissimilar antecedents. (Contributed by NM, 4-Mar-1995.)
⊢ (𝜑 → (𝜓 ↔ 𝜒))    &   ⊢ (𝜃 → (𝜒 ↔ 𝜏))    ⇒   ⊢ ((𝜑 ∧ 𝜃) → (𝜓 ↔ 𝜏))
Theorem	sylan9bbr 520	Nested syllogism inference conjoining dissimilar antecedents. (Contributed by NM, 4-Mar-1995.)
⊢ (𝜑 → (𝜓 ↔ 𝜒))    &   ⊢ (𝜃 → (𝜒 ↔ 𝜏))    ⇒   ⊢ ((𝜃 ∧ 𝜑) → (𝜓 ↔ 𝜏))
Theorem	jca 521	Deduce conjunction of the consequents of two implications ("join consequents with 'and'"). Deduction form of pm3.2 475 and pm3.2i 476. Its associated deduction is jcad 522. Equivalent to the natural deduction rule ∧ I (∧ introduction), see natded 30769. (Contributed by NM, 3-Jan-1993.) (Proof shortened by Wolf Lammen, 25-Oct-2012.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜑 → 𝜒)    ⇒   ⊢ (𝜑 → (𝜓 ∧ 𝜒))
Theorem	jcad 522	Deduction conjoining the consequents of two implications. Deduction form of jca 521 and double deduction form of pm3.2 475 and pm3.2i 476. (Contributed by NM, 15-Jul-1993.) (Proof shortened by Wolf Lammen, 23-Jul-2013.)
⊢ (𝜑 → (𝜓 → 𝜒))    &   ⊢ (𝜑 → (𝜓 → 𝜃))    ⇒   ⊢ (𝜑 → (𝜓 → (𝜒 ∧ 𝜃)))
Theorem	jca2 523	Inference conjoining the consequents of two implications. (Contributed by Rodolfo Medina, 12-Oct-2010.)
⊢ (𝜑 → (𝜓 → 𝜒))    &   ⊢ (𝜓 → 𝜃)    ⇒   ⊢ (𝜑 → (𝜓 → (𝜒 ∧ 𝜃)))
Theorem	jca31 524	Join three consequents. (Contributed by Jeff Hankins, 1-Aug-2009.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜑 → 𝜒)    &   ⊢ (𝜑 → 𝜃)    ⇒   ⊢ (𝜑 → ((𝜓 ∧ 𝜒) ∧ 𝜃))
Theorem	jca32 525	Join three consequents. (Contributed by FL, 1-Aug-2009.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜑 → 𝜒)    &   ⊢ (𝜑 → 𝜃)    ⇒   ⊢ (𝜑 → (𝜓 ∧ (𝜒 ∧ 𝜃)))
Theorem	jcai 526	Deduction replacing implication with conjunction. (Contributed by NM, 15-Jul-1993.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ (𝜑 → (𝜓 ∧ 𝜒))
Theorem	jcab 527	Distributive law for implication over conjunction. Compare Theorem *4.76 of [WhiteheadRussell] p. 121. (Contributed by NM, 3-Apr-1994.) (Proof shortened by Wolf Lammen, 27-Nov-2013.)
⊢ ((𝜑 → (𝜓 ∧ 𝜒)) ↔ ((𝜑 → 𝜓) ∧ (𝜑 → 𝜒)))
Theorem	pm4.76 528	Theorem *4.76 of [WhiteheadRussell] p. 121. (Contributed by NM, 3-Jan-2005.)
⊢ (((𝜑 → 𝜓) ∧ (𝜑 → 𝜒)) ↔ (𝜑 → (𝜓 ∧ 𝜒)))
Theorem	jctil 529	Inference conjoining a theorem to left of consequent in an implication. (Contributed by NM, 31-Dec-1993.)
⊢ (𝜑 → 𝜓)    &   ⊢ 𝜒    ⇒   ⊢ (𝜑 → (𝜒 ∧ 𝜓))
Theorem	jctir 530	Inference conjoining a theorem to right of consequent in an implication. (Contributed by NM, 31-Dec-1993.)
⊢ (𝜑 → 𝜓)    &   ⊢ 𝜒    ⇒   ⊢ (𝜑 → (𝜓 ∧ 𝜒))
Theorem	jccir 531	Inference conjoining a consequent of a consequent to the right of the consequent in an implication. See also ex-natded5.3i 30775. (Contributed by Mario Carneiro, 9-Feb-2017.) (Revised by AV, 20-Aug-2019.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜓 → 𝜒)    ⇒   ⊢ (𝜑 → (𝜓 ∧ 𝜒))
Theorem	jccil 532	Inference conjoining a consequent of a consequent to the left of the consequent in an implication. Remark: One can also prove this theorem using syl 18 and jca 521 (as done in jccir 531), which would be 4 bytes shorter, but one step longer than the current proof. (Proof modification is discouraged.) (Contributed by AV, 20-Aug-2019.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜓 → 𝜒)    ⇒   ⊢ (𝜑 → (𝜒 ∧ 𝜓))
Theorem	jctl 533	Inference conjoining a theorem to the left of a consequent. (Contributed by NM, 31-Dec-1993.) (Proof shortened by Wolf Lammen, 24-Oct-2012.)
⊢ 𝜓    ⇒   ⊢ (𝜑 → (𝜓 ∧ 𝜑))
Theorem	jctr 534	Inference conjoining a theorem to the right of a consequent. (Contributed by NM, 18-Aug-1993.) (Proof shortened by Wolf Lammen, 24-Oct-2012.)
⊢ 𝜓    ⇒   ⊢ (𝜑 → (𝜑 ∧ 𝜓))
Theorem	jctild 535	Deduction conjoining a theorem to left of consequent in an implication. (Contributed by NM, 21-Apr-2005.)
⊢ (𝜑 → (𝜓 → 𝜒))    &   ⊢ (𝜑 → 𝜃)    ⇒   ⊢ (𝜑 → (𝜓 → (𝜃 ∧ 𝜒)))
Theorem	jctird 536	Deduction conjoining a theorem to right of consequent in an implication. (Contributed by NM, 21-Apr-2005.)
⊢ (𝜑 → (𝜓 → 𝜒))    &   ⊢ (𝜑 → 𝜃)    ⇒   ⊢ (𝜑 → (𝜓 → (𝜒 ∧ 𝜃)))
Theorem	iba 537	Introduction of antecedent as conjunct. Theorem *4.73 of [WhiteheadRussell] p. 121. (Contributed by NM, 30-Mar-1994.)
⊢ (𝜑 → (𝜓 ↔ (𝜓 ∧ 𝜑)))
Theorem	ibar 538	Introduction of antecedent as conjunct. (Contributed by NM, 5-Dec-1995.)
⊢ (𝜑 → (𝜓 ↔ (𝜑 ∧ 𝜓)))
Theorem	biantru 539	A wff is equivalent to its conjunction with truth. (Contributed by NM, 26-May-1993.)
⊢ 𝜑    ⇒   ⊢ (𝜓 ↔ (𝜓 ∧ 𝜑))
Theorem	biantrur 540	A wff is equivalent to its conjunction with truth. (Contributed by NM, 3-Aug-1994.)
⊢ 𝜑    ⇒   ⊢ (𝜓 ↔ (𝜑 ∧ 𝜓))
Theorem	biantrud 541	A wff is equivalent to its conjunction with truth. (Contributed by NM, 2-Aug-1994.) (Proof shortened by Wolf Lammen, 23-Oct-2013.)
⊢ (𝜑 → 𝜓)    ⇒   ⊢ (𝜑 → (𝜒 ↔ (𝜒 ∧ 𝜓)))
Theorem	biantrurd 542	A wff is equivalent to its conjunction with truth. (Contributed by NM, 1-May-1995.) (Proof shortened by Andrew Salmon, 7-May-2011.)
⊢ (𝜑 → 𝜓)    ⇒   ⊢ (𝜑 → (𝜒 ↔ (𝜓 ∧ 𝜒)))
Theorem	bianfi 543	A wff conjoined with falsehood is false. (Contributed by NM, 21-Jun-1993.) (Proof shortened by Wolf Lammen, 26-Nov-2012.)
⊢ ¬ 𝜑    ⇒   ⊢ (𝜑 ↔ (𝜓 ∧ 𝜑))
Theorem	bianfd 544	A wff conjoined with falsehood is false. (Contributed by NM, 27-Mar-1995.) (Proof shortened by Wolf Lammen, 5-Nov-2013.)
⊢ (𝜑 → ¬ 𝜓)    ⇒   ⊢ (𝜑 → (𝜓 ↔ (𝜓 ∧ 𝜒)))
Theorem	baib 545	Move conjunction outside of biconditional. (Contributed by NM, 13-May-1999.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜓 → (𝜑 ↔ 𝜒))
Theorem	baibr 546	Move conjunction outside of biconditional. (Contributed by NM, 11-Jul-1994.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜓 → (𝜒 ↔ 𝜑))
Theorem	rbaibr 547	Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.) (Proof shortened by Wolf Lammen, 19-Jan-2020.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜒 → (𝜓 ↔ 𝜑))
Theorem	rbaib 548	Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.) (Proof shortened by Wolf Lammen, 19-Jan-2020.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜒 → (𝜑 ↔ 𝜓))
Theorem	baibd 549	Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.)
⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃)))    ⇒   ⊢ ((𝜑 ∧ 𝜒) → (𝜓 ↔ 𝜃))
Theorem	rbaibd 550	Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.)
⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃)))    ⇒   ⊢ ((𝜑 ∧ 𝜃) → (𝜓 ↔ 𝜒))
Theorem	bianabs 551	Absorb a hypothesis into the second member of a biconditional. (Contributed by FL, 15-Feb-2007.)
⊢ (𝜑 → (𝜓 ↔ (𝜑 ∧ 𝜒)))    ⇒   ⊢ (𝜑 → (𝜓 ↔ 𝜒))
Theorem	pm5.44 552	Theorem *5.44 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.)
⊢ ((𝜑 → 𝜓) → ((𝜑 → 𝜒) ↔ (𝜑 → (𝜓 ∧ 𝜒))))
Theorem	pm5.42 553	Theorem *5.42 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.)
⊢ ((𝜑 → (𝜓 → 𝜒)) ↔ (𝜑 → (𝜓 → (𝜑 ∧ 𝜒))))
Theorem	ancl 554	Conjoin antecedent to left of consequent. (Contributed by NM, 15-Aug-1994.)
⊢ ((𝜑 → 𝜓) → (𝜑 → (𝜑 ∧ 𝜓)))
Theorem	anclb 555	Conjoin antecedent to left of consequent. Theorem *4.7 of [WhiteheadRussell] p. 120. (Contributed by NM, 25-Jul-1999.) (Proof shortened by Wolf Lammen, 24-Mar-2013.)
⊢ ((𝜑 → 𝜓) ↔ (𝜑 → (𝜑 ∧ 𝜓)))
Theorem	ancr 556	Conjoin antecedent to right of consequent. (Contributed by NM, 15-Aug-1994.)
⊢ ((𝜑 → 𝜓) → (𝜑 → (𝜓 ∧ 𝜑)))
Theorem	ancrb 557	Conjoin antecedent to right of consequent. (Contributed by NM, 25-Jul-1999.) (Proof shortened by Wolf Lammen, 24-Mar-2013.)
⊢ ((𝜑 → 𝜓) ↔ (𝜑 → (𝜓 ∧ 𝜑)))
Theorem	ancli 558	Deduction conjoining antecedent to left of consequent. (Contributed by NM, 12-Aug-1993.)
⊢ (𝜑 → 𝜓)    ⇒   ⊢ (𝜑 → (𝜑 ∧ 𝜓))
Theorem	ancri 559	Deduction conjoining antecedent to right of consequent. (Contributed by NM, 15-Aug-1994.)
⊢ (𝜑 → 𝜓)    ⇒   ⊢ (𝜑 → (𝜓 ∧ 𝜑))
Theorem	ancld 560	Deduction conjoining antecedent to left of consequent in nested implication. (Contributed by NM, 15-Aug-1994.) (Proof shortened by Wolf Lammen, 1-Nov-2012.)
⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ (𝜑 → (𝜓 → (𝜓 ∧ 𝜒)))
Theorem	ancrd 561	Deduction conjoining antecedent to right of consequent in nested implication. (Contributed by NM, 15-Aug-1994.) (Proof shortened by Wolf Lammen, 1-Nov-2012.)
⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ (𝜑 → (𝜓 → (𝜒 ∧ 𝜓)))
Theorem	impac 562	Importation with conjunction in consequent. (Contributed by NM, 9-Aug-1994.)
⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ ((𝜑 ∧ 𝜓) → (𝜒 ∧ 𝜓))
Theorem	anc2l 563	Conjoin antecedent to left of consequent in nested implication. (Contributed by NM, 10-Aug-1994.) (Proof shortened by Wolf Lammen, 14-Jul-2013.)
⊢ ((𝜑 → (𝜓 → 𝜒)) → (𝜑 → (𝜓 → (𝜑 ∧ 𝜒))))
Theorem	anc2r 564	Conjoin antecedent to right of consequent in nested implication. (Contributed by NM, 15-Aug-1994.)
⊢ ((𝜑 → (𝜓 → 𝜒)) → (𝜑 → (𝜓 → (𝜒 ∧ 𝜑))))
Theorem	anc2li 565	Deduction conjoining antecedent to left of consequent in nested implication. (Contributed by NM, 10-Aug-1994.) (Proof shortened by Wolf Lammen, 7-Dec-2012.)
⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ (𝜑 → (𝜓 → (𝜑 ∧ 𝜒)))
Theorem	anc2ri 566	Deduction conjoining antecedent to right of consequent in nested implication. (Contributed by NM, 15-Aug-1994.) (Proof shortened by Wolf Lammen, 7-Dec-2012.)
⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ (𝜑 → (𝜓 → (𝜒 ∧ 𝜑)))
Theorem	pm4.71 567	Implication in terms of biconditional and conjunction. Theorem *4.71 of [WhiteheadRussell] p. 120. (Contributed by NM, 21-Jun-1993.) (Proof shortened by Wolf Lammen, 2-Dec-2012.)
⊢ ((𝜑 → 𝜓) ↔ (𝜑 ↔ (𝜑 ∧ 𝜓)))
Theorem	pm4.71r 568	Implication in terms of biconditional and conjunction. Theorem *4.71 of [WhiteheadRussell] p. 120 (with conjunct reversed). (Contributed by NM, 25-Jul-1999.)
⊢ ((𝜑 → 𝜓) ↔ (𝜑 ↔ (𝜓 ∧ 𝜑)))
Theorem	pm4.71i 569	Inference converting an implication to a biconditional with conjunction. Inference from Theorem *4.71 of [WhiteheadRussell] p. 120. (Contributed by NM, 4-Jan-2004.)
⊢ (𝜑 → 𝜓)    ⇒   ⊢ (𝜑 ↔ (𝜑 ∧ 𝜓))
Theorem	pm4.71ri 570	Inference converting an implication to a biconditional with conjunction. Inference from Theorem *4.71 of [WhiteheadRussell] p. 120 (with conjunct reversed). (Contributed by NM, 1-Dec-2003.)
⊢ (𝜑 → 𝜓)    ⇒   ⊢ (𝜑 ↔ (𝜓 ∧ 𝜑))
Theorem	pm4.71d 571	Deduction converting an implication to a biconditional with conjunction. Deduction from Theorem *4.71 of [WhiteheadRussell] p. 120. (Contributed by Mario Carneiro, 25-Dec-2016.)
⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ (𝜑 → (𝜓 ↔ (𝜓 ∧ 𝜒)))
Theorem	pm4.71rd 572	Deduction converting an implication to a biconditional with conjunction. Deduction from Theorem *4.71 of [WhiteheadRussell] p. 120. (Contributed by NM, 10-Feb-2005.)
⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜓)))
Theorem	pm4.71da 573	Deduction converting a biconditional to a biconditional with conjunction. Variant of pm4.71d 571. (Contributed by Zhi Wang, 30-Aug-2024.)
⊢ (𝜑 → (𝜓 ↔ 𝜒))    ⇒   ⊢ (𝜑 → (𝜓 ↔ (𝜓 ∧ 𝜒)))
Theorem	pm4.24 574	Theorem *4.24 of [WhiteheadRussell] p. 117. (Contributed by NM, 11-May-1993.)
⊢ (𝜑 ↔ (𝜑 ∧ 𝜑))
Theorem	anidm 575	Idempotent law for conjunction. (Contributed by NM, 8-Jan-2004.) (Proof shortened by Wolf Lammen, 14-Mar-2014.)
⊢ ((𝜑 ∧ 𝜑) ↔ 𝜑)
Theorem	anidmdbi 576	Conjunction idempotence with antecedent. (Contributed by Roy F. Longton, 8-Aug-2005.)
⊢ ((𝜑 → (𝜓 ∧ 𝜓)) ↔ (𝜑 → 𝜓))
Theorem	anidms 577	Inference from idempotent law for conjunction. (Contributed by NM, 15-Jun-1994.)
⊢ ((𝜑 ∧ 𝜑) → 𝜓)    ⇒   ⊢ (𝜑 → 𝜓)
Theorem	imdistan 578	Distribution of implication with conjunction. (Contributed by NM, 31-May-1999.) (Proof shortened by Wolf Lammen, 6-Dec-2012.)
⊢ ((𝜑 → (𝜓 → 𝜒)) ↔ ((𝜑 ∧ 𝜓) → (𝜑 ∧ 𝜒)))
Theorem	imdistani 579	Distribution of implication with conjunction. (Contributed by NM, 1-Aug-1994.)
⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ ((𝜑 ∧ 𝜓) → (𝜑 ∧ 𝜒))
Theorem	imdistanri 580	Distribution of implication with conjunction. (Contributed by NM, 8-Jan-2002.)
⊢ (𝜑 → (𝜓 → 𝜒))    ⇒   ⊢ ((𝜓 ∧ 𝜑) → (𝜒 ∧ 𝜑))
Theorem	imdistand 581	Distribution of implication with conjunction (deduction form). (Contributed by NM, 27-Aug-2004.)
⊢ (𝜑 → (𝜓 → (𝜒 → 𝜃)))    ⇒   ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → (𝜓 ∧ 𝜃)))
Theorem	imdistanda 582	Distribution of implication with conjunction (deduction version with conjoined antecedent). (Contributed by Jeff Madsen, 19-Jun-2011.)
⊢ ((𝜑 ∧ 𝜓) → (𝜒 → 𝜃))    ⇒   ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → (𝜓 ∧ 𝜃)))
Theorem	pm5.3 583	Theorem *5.3 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Andrew Salmon, 7-May-2011.)
⊢ (((𝜑 ∧ 𝜓) → 𝜒) ↔ ((𝜑 ∧ 𝜓) → (𝜑 ∧ 𝜒)))
Theorem	pm5.32 584	Distribution of implication over biconditional. Theorem *5.32 of [WhiteheadRussell] p. 125. (Contributed by NM, 1-Aug-1994.)
⊢ ((𝜑 → (𝜓 ↔ 𝜒)) ↔ ((𝜑 ∧ 𝜓) ↔ (𝜑 ∧ 𝜒)))
Theorem	pm5.32i 585	Distribution of implication over biconditional (inference form). (Contributed by NM, 1-Aug-1994.)
⊢ (𝜑 → (𝜓 ↔ 𝜒))    ⇒   ⊢ ((𝜑 ∧ 𝜓) ↔ (𝜑 ∧ 𝜒))
Theorem	pm5.32ri 586	Distribution of implication over biconditional (inference form). (Contributed by NM, 12-Mar-1995.)
⊢ (𝜑 → (𝜓 ↔ 𝜒))    ⇒   ⊢ ((𝜓 ∧ 𝜑) ↔ (𝜒 ∧ 𝜑))
Theorem	bianim 587	Exchanging conjunction in a biconditional. (Contributed by Peter Mazsa, 31-Jul-2023.)
⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))    &   ⊢ (𝜒 → (𝜓 ↔ 𝜃))    ⇒   ⊢ (𝜑 ↔ (𝜃 ∧ 𝜒))
Theorem	pm5.32d 588	Distribution of implication over biconditional (deduction form). (Contributed by NM, 29-Oct-1996.)
⊢ (𝜑 → (𝜓 → (𝜒 ↔ 𝜃)))    ⇒   ⊢ (𝜑 → ((𝜓 ∧ 𝜒) ↔ (𝜓 ∧ 𝜃)))
Theorem	pm5.32rd 589	Distribution of implication over biconditional (deduction form). (Contributed by NM, 25-Dec-2004.)
⊢ (𝜑 → (𝜓 → (𝜒 ↔ 𝜃)))    ⇒   ⊢ (𝜑 → ((𝜒 ∧ 𝜓) ↔ (𝜃 ∧ 𝜓)))
Theorem	pm5.32da 590	Distribution of implication over biconditional (deduction form). (Contributed by NM, 9-Dec-2006.)
⊢ ((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃))    ⇒   ⊢ (𝜑 → ((𝜓 ∧ 𝜒) ↔ (𝜓 ∧ 𝜃)))
Theorem	bian1d 591	Adding a superfluous conjunct in a biconditional. (Contributed by Thierry Arnoux, 26-Feb-2017.) (Proof shortened by Hongxiu Chen, 29-Jun-2025.) (Proof shortened by Peter Mazsa, 24-Feb-2026.)
⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃)))    ⇒   ⊢ (𝜑 → ((𝜒 ∧ 𝜓) ↔ (𝜒 ∧ 𝜃)))
Theorem	sylan 592	A syllogism inference. (Contributed by NM, 21-Apr-1994.) (Proof shortened by Wolf Lammen, 22-Nov-2012.)
⊢ (𝜑 → 𝜓)    &   ⊢ ((𝜓 ∧ 𝜒) → 𝜃)    ⇒   ⊢ ((𝜑 ∧ 𝜒) → 𝜃)
Theorem	sylanb 593	A syllogism inference. (Contributed by NM, 18-May-1994.)
⊢ (𝜑 ↔ 𝜓)    &   ⊢ ((𝜓 ∧ 𝜒) → 𝜃)    ⇒   ⊢ ((𝜑 ∧ 𝜒) → 𝜃)
Theorem	sylanbr 594	A syllogism inference. (Contributed by NM, 18-May-1994.)
⊢ (𝜓 ↔ 𝜑)    &   ⊢ ((𝜓 ∧ 𝜒) → 𝜃)    ⇒   ⊢ ((𝜑 ∧ 𝜒) → 𝜃)
Theorem	sylanbrc 595	Syllogism inference. (Contributed by Jeff Madsen, 2-Sep-2009.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜑 → 𝜒)    &   ⊢ (𝜃 ↔ (𝜓 ∧ 𝜒))    ⇒   ⊢ (𝜑 → 𝜃)
Theorem	syl2anc 596	Syllogism inference combined with contraction. (Contributed by NM, 16-Mar-2012.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜑 → 𝜒)    &   ⊢ ((𝜓 ∧ 𝜒) → 𝜃)    ⇒   ⊢ (𝜑 → 𝜃)
Theorem	syl2anc2 597	Double syllogism inference combined with contraction. (Contributed by BTernaryTau, 29-Sep-2023.)
⊢ (𝜑 → 𝜓)    &   ⊢ (𝜓 → 𝜒)    &   ⊢ ((𝜓 ∧ 𝜒) → 𝜃)    ⇒   ⊢ (𝜑 → 𝜃)
Theorem	sylancl 598	Syllogism inference combined with modus ponens. (Contributed by Jeff Madsen, 2-Sep-2009.)
⊢ (𝜑 → 𝜓)    &   ⊢ 𝜒    &   ⊢ ((𝜓 ∧ 𝜒) → 𝜃)    ⇒   ⊢ (𝜑 → 𝜃)
Theorem	sylancr 599	Syllogism inference combined with modus ponens. (Contributed by Jeff Madsen, 2-Sep-2009.)
⊢ 𝜓    &   ⊢ (𝜑 → 𝜒)    &   ⊢ ((𝜓 ∧ 𝜒) → 𝜃)    ⇒   ⊢ (𝜑 → 𝜃)
Theorem	sylancom 600	Syllogism inference with commutation of antecedents. (Contributed by NM, 2-Jul-2008.)
⊢ ((𝜑 ∧ 𝜓) → 𝜒)    &   ⊢ ((𝜒 ∧ 𝜓) → 𝜃)    ⇒   ⊢ ((𝜑 ∧ 𝜓) → 𝜃)