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Theorem in13 4198
Description: A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.)
Assertion
Ref Expression
in13 (𝐴 ∩ (𝐵𝐶)) = (𝐶 ∩ (𝐵𝐴))

Proof of Theorem in13
StepHypRef Expression
1 in32 4197 . 2 ((𝐵𝐶) ∩ 𝐴) = ((𝐵𝐴) ∩ 𝐶)
2 incom 4177 . 2 (𝐴 ∩ (𝐵𝐶)) = ((𝐵𝐶) ∩ 𝐴)
3 incom 4177 . 2 (𝐶 ∩ (𝐵𝐴)) = ((𝐵𝐴) ∩ 𝐶)
41, 2, 33eqtr4i 2854 1 (𝐴 ∩ (𝐵𝐶)) = (𝐶 ∩ (𝐵𝐴))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1533  cin 3934
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1792  ax-4 1806  ax-5 1907  ax-6 1966  ax-7 2011  ax-8 2112  ax-9 2120  ax-10 2141  ax-11 2157  ax-12 2173  ax-ext 2793
This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-tru 1536  df-ex 1777  df-nf 1781  df-sb 2066  df-clab 2800  df-cleq 2814  df-clel 2893  df-nfc 2963  df-rab 3147  df-v 3496  df-in 3942
This theorem is referenced by:  inin  30271
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