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Theorem in31 4154
Description: A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.)
Assertion
Ref Expression
in31 ((𝐴𝐵) ∩ 𝐶) = ((𝐶𝐵) ∩ 𝐴)

Proof of Theorem in31
StepHypRef Expression
1 in12 4151 . 2 (𝐶 ∩ (𝐴𝐵)) = (𝐴 ∩ (𝐶𝐵))
2 incom 4131 . 2 ((𝐴𝐵) ∩ 𝐶) = (𝐶 ∩ (𝐴𝐵))
3 incom 4131 . 2 ((𝐶𝐵) ∩ 𝐴) = (𝐴 ∩ (𝐶𝐵))
41, 2, 33eqtr4i 2776 1 ((𝐴𝐵) ∩ 𝐶) = ((𝐶𝐵) ∩ 𝐴)
Colors of variables: wff setvar class
Syntax hints:   = wceq 1539  cin 3882
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1799  ax-4 1813  ax-5 1914  ax-6 1972  ax-7 2012  ax-8 2110  ax-9 2118  ax-ext 2709
This theorem depends on definitions:  df-bi 206  df-an 396  df-tru 1542  df-ex 1784  df-sb 2069  df-clab 2716  df-cleq 2730  df-clel 2817  df-rab 3072  df-v 3424  df-in 3890
This theorem is referenced by:  inrot  4155
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