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Theorem List for Metamath Proof Explorer - 4201-4300   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremineq2i 4201 Equality inference for intersection of two classes. (Contributed by NM, 26-Dec-1993.)
𝐴 = 𝐵       (𝐶𝐴) = (𝐶𝐵)
 
Theoremineq12i 4202 Equality inference for intersection of two classes. (Contributed by NM, 24-Jun-2004.) (Proof shortened by Eric Schmidt, 26-Jan-2007.)
𝐴 = 𝐵    &   𝐶 = 𝐷       (𝐴𝐶) = (𝐵𝐷)
 
Theoremineq1d 4203 Equality deduction for intersection of two classes. (Contributed by NM, 10-Apr-1994.)
(𝜑𝐴 = 𝐵)       (𝜑 → (𝐴𝐶) = (𝐵𝐶))
 
Theoremineq2d 4204 Equality deduction for intersection of two classes. (Contributed by NM, 10-Apr-1994.)
(𝜑𝐴 = 𝐵)       (𝜑 → (𝐶𝐴) = (𝐶𝐵))
 
Theoremineq12d 4205 Equality deduction for intersection of two classes. (Contributed by NM, 24-Jun-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
(𝜑𝐴 = 𝐵)    &   (𝜑𝐶 = 𝐷)       (𝜑 → (𝐴𝐶) = (𝐵𝐷))
 
Theoremineqan12d 4206 Equality deduction for intersection of two classes. (Contributed by NM, 7-Feb-2007.)
(𝜑𝐴 = 𝐵)    &   (𝜓𝐶 = 𝐷)       ((𝜑𝜓) → (𝐴𝐶) = (𝐵𝐷))
 
Theoremsseqin2 4207 A relationship between subclass and intersection. Similar to Exercise 9 of [TakeutiZaring] p. 18. (Contributed by NM, 17-May-1994.)
(𝐴𝐵 ↔ (𝐵𝐴) = 𝐴)
 
Theoremnfin 4208 Bound-variable hypothesis builder for the intersection of classes. (Contributed by NM, 15-Sep-2003.) (Revised by Mario Carneiro, 14-Oct-2016.)
𝑥𝐴    &   𝑥𝐵       𝑥(𝐴𝐵)
 
Theoremrabbi2dva 4209* Deduction from a wff to a restricted class abstraction. (Contributed by NM, 14-Jan-2014.)
((𝜑𝑥𝐴) → (𝑥𝐵𝜓))       (𝜑 → (𝐴𝐵) = {𝑥𝐴𝜓})
 
Theoreminidm 4210 Idempotent law for intersection of classes. Theorem 15 of [Suppes] p. 26. (Contributed by NM, 5-Aug-1993.)
(𝐴𝐴) = 𝐴
 
Theoreminass 4211 Associative law for intersection of classes. Exercise 9 of [TakeutiZaring] p. 17. (Contributed by NM, 3-May-1994.)
((𝐴𝐵) ∩ 𝐶) = (𝐴 ∩ (𝐵𝐶))
 
Theoremin12 4212 A rearrangement of intersection. (Contributed by NM, 21-Apr-2001.)
(𝐴 ∩ (𝐵𝐶)) = (𝐵 ∩ (𝐴𝐶))
 
Theoremin32 4213 A rearrangement of intersection. (Contributed by NM, 21-Apr-2001.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
((𝐴𝐵) ∩ 𝐶) = ((𝐴𝐶) ∩ 𝐵)
 
Theoremin13 4214 A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.)
(𝐴 ∩ (𝐵𝐶)) = (𝐶 ∩ (𝐵𝐴))
 
Theoremin31 4215 A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.)
((𝐴𝐵) ∩ 𝐶) = ((𝐶𝐵) ∩ 𝐴)
 
Theoreminrot 4216 Rotate the intersection of 3 classes. (Contributed by NM, 27-Aug-2012.)
((𝐴𝐵) ∩ 𝐶) = ((𝐶𝐴) ∩ 𝐵)
 
Theoremin4 4217 Rearrangement of intersection of 4 classes. (Contributed by NM, 21-Apr-2001.)
((𝐴𝐵) ∩ (𝐶𝐷)) = ((𝐴𝐶) ∩ (𝐵𝐷))
 
Theoreminindi 4218 Intersection distributes over itself. (Contributed by NM, 6-May-1994.)
(𝐴 ∩ (𝐵𝐶)) = ((𝐴𝐵) ∩ (𝐴𝐶))
 
Theoreminindir 4219 Intersection distributes over itself. (Contributed by NM, 17-Aug-2004.)
((𝐴𝐵) ∩ 𝐶) = ((𝐴𝐶) ∩ (𝐵𝐶))
 
Theoreminss1 4220 The intersection of two classes is a subset of one of them. Part of Exercise 12 of [TakeutiZaring] p. 18. (Contributed by NM, 27-Apr-1994.)
(𝐴𝐵) ⊆ 𝐴
 
Theoreminss2 4221 The intersection of two classes is a subset of one of them. Part of Exercise 12 of [TakeutiZaring] p. 18. (Contributed by NM, 27-Apr-1994.)
(𝐴𝐵) ⊆ 𝐵
 
Theoremssin 4222 Subclass of intersection. Theorem 2.8(vii) of [Monk1] p. 26. (Contributed by NM, 15-Jun-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
((𝐴𝐵𝐴𝐶) ↔ 𝐴 ⊆ (𝐵𝐶))
 
Theoremssini 4223 An inference showing that a subclass of two classes is a subclass of their intersection. (Contributed by NM, 24-Nov-2003.)
𝐴𝐵    &   𝐴𝐶       𝐴 ⊆ (𝐵𝐶)
 
Theoremssind 4224 A deduction showing that a subclass of two classes is a subclass of their intersection. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.)
(𝜑𝐴𝐵)    &   (𝜑𝐴𝐶)       (𝜑𝐴 ⊆ (𝐵𝐶))
 
Theoremssrin 4225 Add right intersection to subclass relation. (Contributed by NM, 16-Aug-1994.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
(𝐴𝐵 → (𝐴𝐶) ⊆ (𝐵𝐶))
 
Theoremsslin 4226 Add left intersection to subclass relation. (Contributed by NM, 19-Oct-1999.)
(𝐴𝐵 → (𝐶𝐴) ⊆ (𝐶𝐵))
 
Theoremssrind 4227 Add right intersection to subclass relation. (Contributed by Glauco Siliprandi, 2-Jan-2022.)
(𝜑𝐴𝐵)       (𝜑 → (𝐴𝐶) ⊆ (𝐵𝐶))
 
Theoremss2in 4228 Intersection of subclasses. (Contributed by NM, 5-May-2000.)
((𝐴𝐵𝐶𝐷) → (𝐴𝐶) ⊆ (𝐵𝐷))
 
Theoremssinss1 4229 Intersection preserves subclass relationship. (Contributed by NM, 14-Sep-1999.)
(𝐴𝐶 → (𝐴𝐵) ⊆ 𝐶)
 
Theoreminss 4230 Inclusion of an intersection of two classes. (Contributed by NM, 30-Oct-2014.)
((𝐴𝐶𝐵𝐶) → (𝐴𝐵) ⊆ 𝐶)
 
Theoremrexin 4231 Restricted existential quantification over intersection. (Contributed by Peter Mazsa, 17-Dec-2018.)
(∃𝑥 ∈ (𝐴𝐵)𝜑 ↔ ∃𝑥𝐴 (𝑥𝐵𝜑))
 
Theoremdfss7 4232* Alternate definition of subclass relationship. (Contributed by AV, 1-Aug-2022.)
(𝐵𝐴 ↔ {𝑥𝐴𝑥𝐵} = 𝐵)
 
2.1.13.4  The symmetric difference of two classes
 
Syntaxcsymdif 4233 Declare the syntax for symmetric difference.
class (𝐴𝐵)
 
Definitiondf-symdif 4234 Define the symmetric difference of two classes. Alternate definitions are dfsymdif2 4242, dfsymdif3 4288 and dfsymdif4 4240. (Contributed by Scott Fenton, 31-Mar-2012.)
(𝐴𝐵) = ((𝐴𝐵) ∪ (𝐵𝐴))
 
Theoremsymdifcom 4235 Symmetric difference commutes. (Contributed by Scott Fenton, 24-Apr-2012.)
(𝐴𝐵) = (𝐵𝐴)
 
Theoremsymdifeq1 4236 Equality theorem for symmetric difference. (Contributed by Scott Fenton, 24-Apr-2012.)
(𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
 
Theoremsymdifeq2 4237 Equality theorem for symmetric difference. (Contributed by Scott Fenton, 24-Apr-2012.)
(𝐴 = 𝐵 → (𝐶𝐴) = (𝐶𝐵))
 
Theoremnfsymdif 4238 Hypothesis builder for symmetric difference. (Contributed by Scott Fenton, 19-Feb-2013.) (Revised by Mario Carneiro, 11-Dec-2016.)
𝑥𝐴    &   𝑥𝐵       𝑥(𝐴𝐵)
 
Theoremelsymdif 4239 Membership in a symmetric difference. (Contributed by Scott Fenton, 31-Mar-2012.)
(𝐴 ∈ (𝐵𝐶) ↔ ¬ (𝐴𝐵𝐴𝐶))
 
Theoremdfsymdif4 4240* Alternate definition of the symmetric difference. (Contributed by NM, 17-Aug-2004.) (Revised by AV, 17-Aug-2022.)
(𝐴𝐵) = {𝑥 ∣ ¬ (𝑥𝐴𝑥𝐵)}
 
Theoremelsymdifxor 4241 Membership in a symmetric difference is an exclusive-or relationship. (Contributed by David A. Wheeler, 26-Apr-2020.) (Proof shortened by BJ, 13-Aug-2022.)
(𝐴 ∈ (𝐵𝐶) ↔ (𝐴𝐵𝐴𝐶))
 
Theoremdfsymdif2 4242* Alternate definition of the symmetric difference. (Contributed by BJ, 30-Apr-2020.)
(𝐴𝐵) = {𝑥 ∣ (𝑥𝐴𝑥𝐵)}
 
Theoremsymdifass 4243 Symmetric difference is associative. (Contributed by Scott Fenton, 24-Apr-2012.) (Proof shortened by BJ, 7-Sep-2022.)
((𝐴𝐵) △ 𝐶) = (𝐴 △ (𝐵𝐶))
 
Theoremdifsssymdif 4244 The symmetric difference contains one of the differences. (Proposed by BJ, 18-Aug-2022.) (Contributed by AV, 19-Aug-2022.)
(𝐴𝐵) ⊆ (𝐴𝐵)
 
Theoremdifsymssdifssd 4245 If the symmetric difference is contained in 𝐶, so is one of the differences. (Contributed by AV, 17-Aug-2022.)
(𝜑 → (𝐴𝐵) ⊆ 𝐶)       (𝜑 → (𝐴𝐵) ⊆ 𝐶)
 
2.1.13.5  Combinations of difference, union, and intersection of two classes
 
Theoremunabs 4246 Absorption law for union. (Contributed by NM, 16-Apr-2006.)
(𝐴 ∪ (𝐴𝐵)) = 𝐴
 
Theoreminabs 4247 Absorption law for intersection. (Contributed by NM, 16-Apr-2006.)
(𝐴 ∩ (𝐴𝐵)) = 𝐴
 
Theoremnssinpss 4248 Negation of subclass expressed in terms of intersection and proper subclass. (Contributed by NM, 30-Jun-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
𝐴𝐵 ↔ (𝐴𝐵) ⊊ 𝐴)
 
Theoremnsspssun 4249 Negation of subclass expressed in terms of proper subclass and union. (Contributed by NM, 15-Sep-2004.)
𝐴𝐵𝐵 ⊊ (𝐴𝐵))
 
Theoremdfss4 4250 Subclass defined in terms of class difference. See comments under dfun2 4251. (Contributed by NM, 22-Mar-1998.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
(𝐴𝐵 ↔ (𝐵 ∖ (𝐵𝐴)) = 𝐴)
 
Theoremdfun2 4251 An alternate definition of the union of two classes in terms of class difference, requiring no dummy variables. Along with dfin2 4252 and dfss4 4250 it shows we can express union, intersection, and subset directly in terms of the single "primitive" operation (class difference). (Contributed by NM, 10-Jun-2004.)
(𝐴𝐵) = (V ∖ ((V ∖ 𝐴) ∖ 𝐵))
 
Theoremdfin2 4252 An alternate definition of the intersection of two classes in terms of class difference, requiring no dummy variables. See comments under dfun2 4251. Another version is given by dfin4 4259. (Contributed by NM, 10-Jun-2004.)
(𝐴𝐵) = (𝐴 ∖ (V ∖ 𝐵))
 
Theoremdifin 4253 Difference with intersection. Theorem 33 of [Suppes] p. 29. (Contributed by NM, 31-Mar-1998.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
(𝐴 ∖ (𝐴𝐵)) = (𝐴𝐵)
 
Theoremssdifim 4254 Implication of a class difference with a subclass. (Contributed by AV, 3-Jan-2022.)
((𝐴𝑉𝐵 = (𝑉𝐴)) → 𝐴 = (𝑉𝐵))
 
Theoremssdifsym 4255 Symmetric class differences for subclasses. (Contributed by AV, 3-Jan-2022.)
((𝐴𝑉𝐵𝑉) → (𝐵 = (𝑉𝐴) ↔ 𝐴 = (𝑉𝐵)))
 
Theoremdfss5 4256* Alternate definition of subclass relationship: a class 𝐴 is a subclass of another class 𝐵 iff each element of 𝐴 is equal to an element of 𝐵. (Contributed by AV, 13-Nov-2020.)
(𝐴𝐵 ↔ ∀𝑥𝐴𝑦𝐵 𝑥 = 𝑦)
 
Theoremdfun3 4257 Union defined in terms of intersection (De Morgan's law). Definition of union in [Mendelson] p. 231. (Contributed by NM, 8-Jan-2002.)
(𝐴𝐵) = (V ∖ ((V ∖ 𝐴) ∩ (V ∖ 𝐵)))
 
Theoremdfin3 4258 Intersection defined in terms of union (De Morgan's law). Similar to Exercise 4.10(n) of [Mendelson] p. 231. (Contributed by NM, 8-Jan-2002.)
(𝐴𝐵) = (V ∖ ((V ∖ 𝐴) ∪ (V ∖ 𝐵)))
 
Theoremdfin4 4259 Alternate definition of the intersection of two classes. Exercise 4.10(q) of [Mendelson] p. 231. (Contributed by NM, 25-Nov-2003.)
(𝐴𝐵) = (𝐴 ∖ (𝐴𝐵))
 
Theoreminvdif 4260 Intersection with universal complement. Remark in [Stoll] p. 20. (Contributed by NM, 17-Aug-2004.)
(𝐴 ∩ (V ∖ 𝐵)) = (𝐴𝐵)
 
Theoremindif 4261 Intersection with class difference. Theorem 34 of [Suppes] p. 29. (Contributed by NM, 17-Aug-2004.)
(𝐴 ∩ (𝐴𝐵)) = (𝐴𝐵)
 
Theoremindif2 4262 Bring an intersection in and out of a class difference. (Contributed by Jeff Hankins, 15-Jul-2009.)
(𝐴 ∩ (𝐵𝐶)) = ((𝐴𝐵) ∖ 𝐶)
 
Theoremindif1 4263 Bring an intersection in and out of a class difference. (Contributed by Mario Carneiro, 15-May-2015.)
((𝐴𝐶) ∩ 𝐵) = ((𝐴𝐵) ∖ 𝐶)
 
Theoremindifcom 4264 Commutation law for intersection and difference. (Contributed by Scott Fenton, 18-Feb-2013.)
(𝐴 ∩ (𝐵𝐶)) = (𝐵 ∩ (𝐴𝐶))
 
Theoremindi 4265 Distributive law for intersection over union. Exercise 10 of [TakeutiZaring] p. 17. (Contributed by NM, 30-Sep-2002.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
(𝐴 ∩ (𝐵𝐶)) = ((𝐴𝐵) ∪ (𝐴𝐶))
 
Theoremundi 4266 Distributive law for union over intersection. Exercise 11 of [TakeutiZaring] p. 17. (Contributed by NM, 30-Sep-2002.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
(𝐴 ∪ (𝐵𝐶)) = ((𝐴𝐵) ∩ (𝐴𝐶))
 
Theoremindir 4267 Distributive law for intersection over union. Theorem 28 of [Suppes] p. 27. (Contributed by NM, 30-Sep-2002.)
((𝐴𝐵) ∩ 𝐶) = ((𝐴𝐶) ∪ (𝐵𝐶))
 
Theoremundir 4268 Distributive law for union over intersection. Theorem 29 of [Suppes] p. 27. (Contributed by NM, 30-Sep-2002.)
((𝐴𝐵) ∪ 𝐶) = ((𝐴𝐶) ∩ (𝐵𝐶))
 
Theoremunineq 4269 Infer equality from equalities of union and intersection. Exercise 20 of [Enderton] p. 32 and its converse. (Contributed by NM, 10-Aug-2004.)
(((𝐴𝐶) = (𝐵𝐶) ∧ (𝐴𝐶) = (𝐵𝐶)) ↔ 𝐴 = 𝐵)
 
Theoremuneqin 4270 Equality of union and intersection implies equality of their arguments. (Contributed by NM, 16-Apr-2006.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
((𝐴𝐵) = (𝐴𝐵) ↔ 𝐴 = 𝐵)
 
Theoremdifundi 4271 Distributive law for class difference. Theorem 39 of [Suppes] p. 29. (Contributed by NM, 17-Aug-2004.)
(𝐴 ∖ (𝐵𝐶)) = ((𝐴𝐵) ∩ (𝐴𝐶))
 
Theoremdifundir 4272 Distributive law for class difference. (Contributed by NM, 17-Aug-2004.)
((𝐴𝐵) ∖ 𝐶) = ((𝐴𝐶) ∪ (𝐵𝐶))
 
Theoremdifindi 4273 Distributive law for class difference. Theorem 40 of [Suppes] p. 29. (Contributed by NM, 17-Aug-2004.)
(𝐴 ∖ (𝐵𝐶)) = ((𝐴𝐵) ∪ (𝐴𝐶))
 
Theoremdifindir 4274 Distributive law for class difference. (Contributed by NM, 17-Aug-2004.)
((𝐴𝐵) ∖ 𝐶) = ((𝐴𝐶) ∩ (𝐵𝐶))
 
Theoremindifdi 4275 Distribute intersection over difference. (Contributed by BTernaryTau, 14-Aug-2024.)
(𝐴 ∩ (𝐵𝐶)) = ((𝐴𝐵) ∖ (𝐴𝐶))
 
Theoremindifdir 4276 Distribute intersection over difference. (Contributed by Scott Fenton, 14-Apr-2011.) (Revised by BTernaryTau, 14-Aug-2024.)
((𝐴𝐵) ∩ 𝐶) = ((𝐴𝐶) ∖ (𝐵𝐶))
 
TheoremindifdirOLD 4277 Obsolete version of indifdir 4276 as of 14-Aug-2024. (Contributed by Scott Fenton, 14-Apr-2011.) (Proof modification is discouraged.) (New usage is discouraged.)
((𝐴𝐵) ∩ 𝐶) = ((𝐴𝐶) ∖ (𝐵𝐶))
 
Theoremdifdif2 4278 Class difference by a class difference. (Contributed by Thierry Arnoux, 18-Dec-2017.)
(𝐴 ∖ (𝐵𝐶)) = ((𝐴𝐵) ∪ (𝐴𝐶))
 
Theoremundm 4279 De Morgan's law for union. Theorem 5.2(13) of [Stoll] p. 19. (Contributed by NM, 18-Aug-2004.)
(V ∖ (𝐴𝐵)) = ((V ∖ 𝐴) ∩ (V ∖ 𝐵))
 
Theoremindm 4280 De Morgan's law for intersection. Theorem 5.2(13') of [Stoll] p. 19. (Contributed by NM, 18-Aug-2004.)
(V ∖ (𝐴𝐵)) = ((V ∖ 𝐴) ∪ (V ∖ 𝐵))
 
Theoremdifun1 4281 A relationship involving double difference and union. (Contributed by NM, 29-Aug-2004.)
(𝐴 ∖ (𝐵𝐶)) = ((𝐴𝐵) ∖ 𝐶)
 
Theoremundif3 4282 An equality involving class union and class difference. The first equality of Exercise 13 of [TakeutiZaring] p. 22. (Contributed by Alan Sare, 17-Apr-2012.) (Proof shortened by JJ, 13-Jul-2021.)
(𝐴 ∪ (𝐵𝐶)) = ((𝐴𝐵) ∖ (𝐶𝐴))
 
Theoremdifin2 4283 Represent a class difference as an intersection with a larger difference. (Contributed by Jeff Madsen, 2-Sep-2009.)
(𝐴𝐶 → (𝐴𝐵) = ((𝐶𝐵) ∩ 𝐴))
 
Theoremdif32 4284 Swap second and third argument of double difference. (Contributed by NM, 18-Aug-2004.)
((𝐴𝐵) ∖ 𝐶) = ((𝐴𝐶) ∖ 𝐵)
 
Theoremdifabs 4285 Absorption-like law for class difference: you can remove a class only once. (Contributed by FL, 2-Aug-2009.)
((𝐴𝐵) ∖ 𝐵) = (𝐴𝐵)
 
Theoremsscon34b 4286 Relative complementation reverses inclusion of subclasses. Relativized version of complss 4138. (Contributed by RP, 3-Jun-2021.)
((𝐴𝐶𝐵𝐶) → (𝐴𝐵 ↔ (𝐶𝐵) ⊆ (𝐶𝐴)))
 
Theoremrcompleq 4287 Two subclasses are equal if and only if their relative complements are equal. Relativized version of compleq 4139. (Contributed by RP, 10-Jun-2021.)
((𝐴𝐶𝐵𝐶) → (𝐴 = 𝐵 ↔ (𝐶𝐴) = (𝐶𝐵)))
 
Theoremdfsymdif3 4288 Alternate definition of the symmetric difference, given in Example 4.1 of [Stoll] p. 262 (the original definition corresponds to [Stoll] p. 13). (Contributed by NM, 17-Aug-2004.) (Revised by BJ, 30-Apr-2020.)
(𝐴𝐵) = ((𝐴𝐵) ∖ (𝐴𝐵))
 
2.1.13.6  Class abstractions with difference, union, and intersection of two classes
 
Theoremunabw 4289* Union of two class abstractions. Version of unab 4290 using implicit substitution, which does not require ax-8 2100, ax-10 2129, ax-12 2163. (Contributed by Gino Giotto, 15-Oct-2024.)
(𝑥 = 𝑦 → (𝜑𝜒))    &   (𝑥 = 𝑦 → (𝜓𝜃))       ({𝑥𝜑} ∪ {𝑥𝜓}) = {𝑦 ∣ (𝜒𝜃)}
 
Theoremunab 4290 Union of two class abstractions. (Contributed by NM, 29-Sep-2002.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
({𝑥𝜑} ∪ {𝑥𝜓}) = {𝑥 ∣ (𝜑𝜓)}
 
Theoreminab 4291 Intersection of two class abstractions. (Contributed by NM, 29-Sep-2002.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
({𝑥𝜑} ∩ {𝑥𝜓}) = {𝑥 ∣ (𝜑𝜓)}
 
Theoremdifab 4292 Difference of two class abstractions. (Contributed by NM, 23-Oct-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
({𝑥𝜑} ∖ {𝑥𝜓}) = {𝑥 ∣ (𝜑 ∧ ¬ 𝜓)}
 
Theoremabanssl 4293 A class abstraction with a conjunction is a subset of the class abstraction with the left conjunct only. (Contributed by AV, 7-Aug-2024.) (Proof shortened by SN, 22-Aug-2024.)
{𝑓 ∣ (𝜑𝜓)} ⊆ {𝑓𝜑}
 
Theoremabanssr 4294 A class abstraction with a conjunction is a subset of the class abstraction with the right conjunct only. (Contributed by AV, 7-Aug-2024.) (Proof shortened by SN, 22-Aug-2024.)
{𝑓 ∣ (𝜑𝜓)} ⊆ {𝑓𝜓}
 
Theoremnotabw 4295* A class abstraction defined by a negation. Version of notab 4296 using implicit substitution, which does not require ax-10 2129, ax-12 2163. (Contributed by Gino Giotto, 15-Oct-2024.)
(𝑥 = 𝑦 → (𝜑𝜓))       {𝑥 ∣ ¬ 𝜑} = (V ∖ {𝑦𝜓})
 
Theoremnotab 4296 A class abstraction defined by a negation. (Contributed by FL, 18-Sep-2010.)
{𝑥 ∣ ¬ 𝜑} = (V ∖ {𝑥𝜑})
 
Theoremunrab 4297 Union of two restricted class abstractions. (Contributed by NM, 25-Mar-2004.)
({𝑥𝐴𝜑} ∪ {𝑥𝐴𝜓}) = {𝑥𝐴 ∣ (𝜑𝜓)}
 
Theoreminrab 4298 Intersection of two restricted class abstractions. (Contributed by NM, 1-Sep-2006.)
({𝑥𝐴𝜑} ∩ {𝑥𝐴𝜓}) = {𝑥𝐴 ∣ (𝜑𝜓)}
 
Theoreminrab2 4299* Intersection with a restricted class abstraction. (Contributed by NM, 19-Nov-2007.)
({𝑥𝐴𝜑} ∩ 𝐵) = {𝑥 ∈ (𝐴𝐵) ∣ 𝜑}
 
Theoremdifrab 4300 Difference of two restricted class abstractions. (Contributed by NM, 23-Oct-2004.)
({𝑥𝐴𝜑} ∖ {𝑥𝐴𝜓}) = {𝑥𝐴 ∣ (𝜑 ∧ ¬ 𝜓)}
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