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Type | Label | Description |
---|---|---|
Statement | ||
Theorem | incom 4201 | Commutative law for intersection of classes. Exercise 7 of [TakeutiZaring] p. 17. (Contributed by NM, 21-Jun-1993.) (Proof shortened by SN, 12-Dec-2023.) |
⊢ (𝐴 ∩ 𝐵) = (𝐵 ∩ 𝐴) | ||
Theorem | ineqcom 4202 | Two ways of expressing that two classes have a given intersection. This is often used when that given intersection is the empty set, in which case the statement displays two ways of expressing that two classes are disjoint (when 𝐶 = ∅: ((𝐴 ∩ 𝐵) = ∅ ↔ (𝐵 ∩ 𝐴) = ∅)). (Contributed by Peter Mazsa, 22-Mar-2017.) |
⊢ ((𝐴 ∩ 𝐵) = 𝐶 ↔ (𝐵 ∩ 𝐴) = 𝐶) | ||
Theorem | ineqcomi 4203 | Two ways of expressing that two classes have a given intersection. Inference form of ineqcom 4202. Disjointness inference when 𝐶 = ∅. (Contributed by Peter Mazsa, 26-Mar-2017.) (Proof shortened by SN, 20-Sep-2024.) |
⊢ (𝐴 ∩ 𝐵) = 𝐶 ⇒ ⊢ (𝐵 ∩ 𝐴) = 𝐶 | ||
Theorem | ineqri 4204* | Inference from membership to intersection. (Contributed by NM, 21-Jun-1993.) |
⊢ ((𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐵) ↔ 𝑥 ∈ 𝐶) ⇒ ⊢ (𝐴 ∩ 𝐵) = 𝐶 | ||
Theorem | ineq1 4205 | Equality theorem for intersection of two classes. (Contributed by NM, 14-Dec-1993.) (Proof shortened by SN, 20-Sep-2023.) |
⊢ (𝐴 = 𝐵 → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶)) | ||
Theorem | ineq2 4206 | Equality theorem for intersection of two classes. (Contributed by NM, 26-Dec-1993.) |
⊢ (𝐴 = 𝐵 → (𝐶 ∩ 𝐴) = (𝐶 ∩ 𝐵)) | ||
Theorem | ineq12 4207 | Equality theorem for intersection of two classes. (Contributed by NM, 8-May-1994.) |
⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷)) | ||
Theorem | ineq1i 4208 | Equality inference for intersection of two classes. (Contributed by NM, 26-Dec-1993.) |
⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶) | ||
Theorem | ineq2i 4209 | Equality inference for intersection of two classes. (Contributed by NM, 26-Dec-1993.) |
⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐶 ∩ 𝐴) = (𝐶 ∩ 𝐵) | ||
Theorem | ineq12i 4210 | Equality inference for intersection of two classes. (Contributed by NM, 24-Jun-2004.) (Proof shortened by Eric Schmidt, 26-Jan-2007.) |
⊢ 𝐴 = 𝐵 & ⊢ 𝐶 = 𝐷 ⇒ ⊢ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷) | ||
Theorem | ineq1d 4211 | Equality deduction for intersection of two classes. (Contributed by NM, 10-Apr-1994.) |
⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶)) | ||
Theorem | ineq2d 4212 | Equality deduction for intersection of two classes. (Contributed by NM, 10-Apr-1994.) |
⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∩ 𝐴) = (𝐶 ∩ 𝐵)) | ||
Theorem | ineq12d 4213 | Equality deduction for intersection of two classes. (Contributed by NM, 24-Jun-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ (𝜑 → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷)) | ||
Theorem | ineqan12d 4214 | Equality deduction for intersection of two classes. (Contributed by NM, 7-Feb-2007.) |
⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ (𝜓 → 𝐶 = 𝐷) ⇒ ⊢ ((𝜑 ∧ 𝜓) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷)) | ||
Theorem | sseqin2 4215 | A relationship between subclass and intersection. Similar to Exercise 9 of [TakeutiZaring] p. 18. (Contributed by NM, 17-May-1994.) |
⊢ (𝐴 ⊆ 𝐵 ↔ (𝐵 ∩ 𝐴) = 𝐴) | ||
Theorem | nfin 4216 | Bound-variable hypothesis builder for the intersection of classes. (Contributed by NM, 15-Sep-2003.) (Revised by Mario Carneiro, 14-Oct-2016.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∩ 𝐵) | ||
Theorem | rabbi2dva 4217* | Deduction from a wff to a restricted class abstraction. (Contributed by NM, 14-Jan-2014.) |
⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → (𝑥 ∈ 𝐵 ↔ 𝜓)) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐵) = {𝑥 ∈ 𝐴 ∣ 𝜓}) | ||
Theorem | inidm 4218 | Idempotent law for intersection of classes. Theorem 15 of [Suppes] p. 26. (Contributed by NM, 5-Aug-1993.) |
⊢ (𝐴 ∩ 𝐴) = 𝐴 | ||
Theorem | inass 4219 | Associative law for intersection of classes. Exercise 9 of [TakeutiZaring] p. 17. (Contributed by NM, 3-May-1994.) |
⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = (𝐴 ∩ (𝐵 ∩ 𝐶)) | ||
Theorem | in12 4220 | A rearrangement of intersection. (Contributed by NM, 21-Apr-2001.) |
⊢ (𝐴 ∩ (𝐵 ∩ 𝐶)) = (𝐵 ∩ (𝐴 ∩ 𝐶)) | ||
Theorem | in32 4221 | A rearrangement of intersection. (Contributed by NM, 21-Apr-2001.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∩ 𝐵) | ||
Theorem | in13 4222 | A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.) |
⊢ (𝐴 ∩ (𝐵 ∩ 𝐶)) = (𝐶 ∩ (𝐵 ∩ 𝐴)) | ||
Theorem | in31 4223 | A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.) |
⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐶 ∩ 𝐵) ∩ 𝐴) | ||
Theorem | inrot 4224 | Rotate the intersection of 3 classes. (Contributed by NM, 27-Aug-2012.) |
⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐶 ∩ 𝐴) ∩ 𝐵) | ||
Theorem | in4 4225 | Rearrangement of intersection of 4 classes. (Contributed by NM, 21-Apr-2001.) |
⊢ ((𝐴 ∩ 𝐵) ∩ (𝐶 ∩ 𝐷)) = ((𝐴 ∩ 𝐶) ∩ (𝐵 ∩ 𝐷)) | ||
Theorem | inindi 4226 | Intersection distributes over itself. (Contributed by NM, 6-May-1994.) |
⊢ (𝐴 ∩ (𝐵 ∩ 𝐶)) = ((𝐴 ∩ 𝐵) ∩ (𝐴 ∩ 𝐶)) | ||
Theorem | inindir 4227 | Intersection distributes over itself. (Contributed by NM, 17-Aug-2004.) |
⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∩ (𝐵 ∩ 𝐶)) | ||
Theorem | inss1 4228 | The intersection of two classes is a subset of one of them. Part of Exercise 12 of [TakeutiZaring] p. 18. (Contributed by NM, 27-Apr-1994.) |
⊢ (𝐴 ∩ 𝐵) ⊆ 𝐴 | ||
Theorem | inss2 4229 | The intersection of two classes is a subset of one of them. Part of Exercise 12 of [TakeutiZaring] p. 18. (Contributed by NM, 27-Apr-1994.) |
⊢ (𝐴 ∩ 𝐵) ⊆ 𝐵 | ||
Theorem | ssin 4230 | Subclass of intersection. Theorem 2.8(vii) of [Monk1] p. 26. (Contributed by NM, 15-Jun-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐴 ⊆ 𝐶) ↔ 𝐴 ⊆ (𝐵 ∩ 𝐶)) | ||
Theorem | ssini 4231 | An inference showing that a subclass of two classes is a subclass of their intersection. (Contributed by NM, 24-Nov-2003.) |
⊢ 𝐴 ⊆ 𝐵 & ⊢ 𝐴 ⊆ 𝐶 ⇒ ⊢ 𝐴 ⊆ (𝐵 ∩ 𝐶) | ||
Theorem | ssind 4232 | A deduction showing that a subclass of two classes is a subclass of their intersection. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) & ⊢ (𝜑 → 𝐴 ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊆ (𝐵 ∩ 𝐶)) | ||
Theorem | ssrin 4233 | Add right intersection to subclass relation. (Contributed by NM, 16-Aug-1994.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∩ 𝐶) ⊆ (𝐵 ∩ 𝐶)) | ||
Theorem | sslin 4234 | Add left intersection to subclass relation. (Contributed by NM, 19-Oct-1999.) |
⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∩ 𝐴) ⊆ (𝐶 ∩ 𝐵)) | ||
Theorem | ssrind 4235 | Add right intersection to subclass relation. (Contributed by Glauco Siliprandi, 2-Jan-2022.) |
⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐶) ⊆ (𝐵 ∩ 𝐶)) | ||
Theorem | ss2in 4236 | Intersection of subclasses. (Contributed by NM, 5-May-2000.) |
⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐶 ⊆ 𝐷) → (𝐴 ∩ 𝐶) ⊆ (𝐵 ∩ 𝐷)) | ||
Theorem | ssinss1 4237 | Intersection preserves subclass relationship. (Contributed by NM, 14-Sep-1999.) |
⊢ (𝐴 ⊆ 𝐶 → (𝐴 ∩ 𝐵) ⊆ 𝐶) | ||
Theorem | inss 4238 | Inclusion of an intersection of two classes. (Contributed by NM, 30-Oct-2014.) |
⊢ ((𝐴 ⊆ 𝐶 ∨ 𝐵 ⊆ 𝐶) → (𝐴 ∩ 𝐵) ⊆ 𝐶) | ||
Theorem | rexin 4239 | Restricted existential quantification over intersection. (Contributed by Peter Mazsa, 17-Dec-2018.) |
⊢ (∃𝑥 ∈ (𝐴 ∩ 𝐵)𝜑 ↔ ∃𝑥 ∈ 𝐴 (𝑥 ∈ 𝐵 ∧ 𝜑)) | ||
Theorem | dfss7 4240* | Alternate definition of subclass relationship. (Contributed by AV, 1-Aug-2022.) |
⊢ (𝐵 ⊆ 𝐴 ↔ {𝑥 ∈ 𝐴 ∣ 𝑥 ∈ 𝐵} = 𝐵) | ||
Syntax | csymdif 4241 | Declare the syntax for symmetric difference. |
class (𝐴 △ 𝐵) | ||
Definition | df-symdif 4242 | Define the symmetric difference of two classes. Alternate definitions are dfsymdif2 4250, dfsymdif3 4296 and dfsymdif4 4248. (Contributed by Scott Fenton, 31-Mar-2012.) |
⊢ (𝐴 △ 𝐵) = ((𝐴 ∖ 𝐵) ∪ (𝐵 ∖ 𝐴)) | ||
Theorem | symdifcom 4243 | Symmetric difference commutes. (Contributed by Scott Fenton, 24-Apr-2012.) |
⊢ (𝐴 △ 𝐵) = (𝐵 △ 𝐴) | ||
Theorem | symdifeq1 4244 | Equality theorem for symmetric difference. (Contributed by Scott Fenton, 24-Apr-2012.) |
⊢ (𝐴 = 𝐵 → (𝐴 △ 𝐶) = (𝐵 △ 𝐶)) | ||
Theorem | symdifeq2 4245 | Equality theorem for symmetric difference. (Contributed by Scott Fenton, 24-Apr-2012.) |
⊢ (𝐴 = 𝐵 → (𝐶 △ 𝐴) = (𝐶 △ 𝐵)) | ||
Theorem | nfsymdif 4246 | Hypothesis builder for symmetric difference. (Contributed by Scott Fenton, 19-Feb-2013.) (Revised by Mario Carneiro, 11-Dec-2016.) |
⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 △ 𝐵) | ||
Theorem | elsymdif 4247 | Membership in a symmetric difference. (Contributed by Scott Fenton, 31-Mar-2012.) |
⊢ (𝐴 ∈ (𝐵 △ 𝐶) ↔ ¬ (𝐴 ∈ 𝐵 ↔ 𝐴 ∈ 𝐶)) | ||
Theorem | dfsymdif4 4248* | Alternate definition of the symmetric difference. (Contributed by NM, 17-Aug-2004.) (Revised by AV, 17-Aug-2022.) |
⊢ (𝐴 △ 𝐵) = {𝑥 ∣ ¬ (𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵)} | ||
Theorem | elsymdifxor 4249 | Membership in a symmetric difference is an exclusive-or relationship. (Contributed by David A. Wheeler, 26-Apr-2020.) (Proof shortened by BJ, 13-Aug-2022.) |
⊢ (𝐴 ∈ (𝐵 △ 𝐶) ↔ (𝐴 ∈ 𝐵 ⊻ 𝐴 ∈ 𝐶)) | ||
Theorem | dfsymdif2 4250* | Alternate definition of the symmetric difference. (Contributed by BJ, 30-Apr-2020.) |
⊢ (𝐴 △ 𝐵) = {𝑥 ∣ (𝑥 ∈ 𝐴 ⊻ 𝑥 ∈ 𝐵)} | ||
Theorem | symdifass 4251 | Symmetric difference is associative. (Contributed by Scott Fenton, 24-Apr-2012.) (Proof shortened by BJ, 7-Sep-2022.) |
⊢ ((𝐴 △ 𝐵) △ 𝐶) = (𝐴 △ (𝐵 △ 𝐶)) | ||
Theorem | difsssymdif 4252 | The symmetric difference contains one of the differences. (Proposed by BJ, 18-Aug-2022.) (Contributed by AV, 19-Aug-2022.) |
⊢ (𝐴 ∖ 𝐵) ⊆ (𝐴 △ 𝐵) | ||
Theorem | difsymssdifssd 4253 | If the symmetric difference is contained in 𝐶, so is one of the differences. (Contributed by AV, 17-Aug-2022.) |
⊢ (𝜑 → (𝐴 △ 𝐵) ⊆ 𝐶) ⇒ ⊢ (𝜑 → (𝐴 ∖ 𝐵) ⊆ 𝐶) | ||
Theorem | unabs 4254 | Absorption law for union. (Contributed by NM, 16-Apr-2006.) |
⊢ (𝐴 ∪ (𝐴 ∩ 𝐵)) = 𝐴 | ||
Theorem | inabs 4255 | Absorption law for intersection. (Contributed by NM, 16-Apr-2006.) |
⊢ (𝐴 ∩ (𝐴 ∪ 𝐵)) = 𝐴 | ||
Theorem | nssinpss 4256 | Negation of subclass expressed in terms of intersection and proper subclass. (Contributed by NM, 30-Jun-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (¬ 𝐴 ⊆ 𝐵 ↔ (𝐴 ∩ 𝐵) ⊊ 𝐴) | ||
Theorem | nsspssun 4257 | Negation of subclass expressed in terms of proper subclass and union. (Contributed by NM, 15-Sep-2004.) |
⊢ (¬ 𝐴 ⊆ 𝐵 ↔ 𝐵 ⊊ (𝐴 ∪ 𝐵)) | ||
Theorem | dfss4 4258 | Subclass defined in terms of class difference. See comments under dfun2 4259. (Contributed by NM, 22-Mar-1998.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 ⊆ 𝐵 ↔ (𝐵 ∖ (𝐵 ∖ 𝐴)) = 𝐴) | ||
Theorem | dfun2 4259 | An alternate definition of the union of two classes in terms of class difference, requiring no dummy variables. Along with dfin2 4260 and dfss4 4258 it shows we can express union, intersection, and subset directly in terms of the single "primitive" operation ∖ (class difference). (Contributed by NM, 10-Jun-2004.) |
⊢ (𝐴 ∪ 𝐵) = (V ∖ ((V ∖ 𝐴) ∖ 𝐵)) | ||
Theorem | dfin2 4260 | An alternate definition of the intersection of two classes in terms of class difference, requiring no dummy variables. See comments under dfun2 4259. Another version is given by dfin4 4267. (Contributed by NM, 10-Jun-2004.) |
⊢ (𝐴 ∩ 𝐵) = (𝐴 ∖ (V ∖ 𝐵)) | ||
Theorem | difin 4261 | Difference with intersection. Theorem 33 of [Suppes] p. 29. (Contributed by NM, 31-Mar-1998.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 ∖ (𝐴 ∩ 𝐵)) = (𝐴 ∖ 𝐵) | ||
Theorem | ssdifim 4262 | Implication of a class difference with a subclass. (Contributed by AV, 3-Jan-2022.) |
⊢ ((𝐴 ⊆ 𝑉 ∧ 𝐵 = (𝑉 ∖ 𝐴)) → 𝐴 = (𝑉 ∖ 𝐵)) | ||
Theorem | ssdifsym 4263 | Symmetric class differences for subclasses. (Contributed by AV, 3-Jan-2022.) |
⊢ ((𝐴 ⊆ 𝑉 ∧ 𝐵 ⊆ 𝑉) → (𝐵 = (𝑉 ∖ 𝐴) ↔ 𝐴 = (𝑉 ∖ 𝐵))) | ||
Theorem | dfss5 4264* | Alternate definition of subclass relationship: a class 𝐴 is a subclass of another class 𝐵 iff each element of 𝐴 is equal to an element of 𝐵. (Contributed by AV, 13-Nov-2020.) |
⊢ (𝐴 ⊆ 𝐵 ↔ ∀𝑥 ∈ 𝐴 ∃𝑦 ∈ 𝐵 𝑥 = 𝑦) | ||
Theorem | dfun3 4265 | Union defined in terms of intersection (De Morgan's law). Definition of union in [Mendelson] p. 231. (Contributed by NM, 8-Jan-2002.) |
⊢ (𝐴 ∪ 𝐵) = (V ∖ ((V ∖ 𝐴) ∩ (V ∖ 𝐵))) | ||
Theorem | dfin3 4266 | Intersection defined in terms of union (De Morgan's law). Similar to Exercise 4.10(n) of [Mendelson] p. 231. (Contributed by NM, 8-Jan-2002.) |
⊢ (𝐴 ∩ 𝐵) = (V ∖ ((V ∖ 𝐴) ∪ (V ∖ 𝐵))) | ||
Theorem | dfin4 4267 | Alternate definition of the intersection of two classes. Exercise 4.10(q) of [Mendelson] p. 231. (Contributed by NM, 25-Nov-2003.) |
⊢ (𝐴 ∩ 𝐵) = (𝐴 ∖ (𝐴 ∖ 𝐵)) | ||
Theorem | invdif 4268 | Intersection with universal complement. Remark in [Stoll] p. 20. (Contributed by NM, 17-Aug-2004.) |
⊢ (𝐴 ∩ (V ∖ 𝐵)) = (𝐴 ∖ 𝐵) | ||
Theorem | indif 4269 | Intersection with class difference. Theorem 34 of [Suppes] p. 29. (Contributed by NM, 17-Aug-2004.) |
⊢ (𝐴 ∩ (𝐴 ∖ 𝐵)) = (𝐴 ∖ 𝐵) | ||
Theorem | indif2 4270 | Bring an intersection in and out of a class difference. (Contributed by Jeff Hankins, 15-Jul-2009.) |
⊢ (𝐴 ∩ (𝐵 ∖ 𝐶)) = ((𝐴 ∩ 𝐵) ∖ 𝐶) | ||
Theorem | indif1 4271 | Bring an intersection in and out of a class difference. (Contributed by Mario Carneiro, 15-May-2015.) |
⊢ ((𝐴 ∖ 𝐶) ∩ 𝐵) = ((𝐴 ∩ 𝐵) ∖ 𝐶) | ||
Theorem | indifcom 4272 | Commutation law for intersection and difference. (Contributed by Scott Fenton, 18-Feb-2013.) |
⊢ (𝐴 ∩ (𝐵 ∖ 𝐶)) = (𝐵 ∩ (𝐴 ∖ 𝐶)) | ||
Theorem | indi 4273 | Distributive law for intersection over union. Exercise 10 of [TakeutiZaring] p. 17. (Contributed by NM, 30-Sep-2002.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 ∩ (𝐵 ∪ 𝐶)) = ((𝐴 ∩ 𝐵) ∪ (𝐴 ∩ 𝐶)) | ||
Theorem | undi 4274 | Distributive law for union over intersection. Exercise 11 of [TakeutiZaring] p. 17. (Contributed by NM, 30-Sep-2002.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ (𝐴 ∪ (𝐵 ∩ 𝐶)) = ((𝐴 ∪ 𝐵) ∩ (𝐴 ∪ 𝐶)) | ||
Theorem | indir 4275 | Distributive law for intersection over union. Theorem 28 of [Suppes] p. 27. (Contributed by NM, 30-Sep-2002.) |
⊢ ((𝐴 ∪ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∪ (𝐵 ∩ 𝐶)) | ||
Theorem | undir 4276 | Distributive law for union over intersection. Theorem 29 of [Suppes] p. 27. (Contributed by NM, 30-Sep-2002.) |
⊢ ((𝐴 ∩ 𝐵) ∪ 𝐶) = ((𝐴 ∪ 𝐶) ∩ (𝐵 ∪ 𝐶)) | ||
Theorem | unineq 4277 | Infer equality from equalities of union and intersection. Exercise 20 of [Enderton] p. 32 and its converse. (Contributed by NM, 10-Aug-2004.) |
⊢ (((𝐴 ∪ 𝐶) = (𝐵 ∪ 𝐶) ∧ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶)) ↔ 𝐴 = 𝐵) | ||
Theorem | uneqin 4278 | Equality of union and intersection implies equality of their arguments. (Contributed by NM, 16-Apr-2006.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ ((𝐴 ∪ 𝐵) = (𝐴 ∩ 𝐵) ↔ 𝐴 = 𝐵) | ||
Theorem | difundi 4279 | Distributive law for class difference. Theorem 39 of [Suppes] p. 29. (Contributed by NM, 17-Aug-2004.) |
⊢ (𝐴 ∖ (𝐵 ∪ 𝐶)) = ((𝐴 ∖ 𝐵) ∩ (𝐴 ∖ 𝐶)) | ||
Theorem | difundir 4280 | Distributive law for class difference. (Contributed by NM, 17-Aug-2004.) |
⊢ ((𝐴 ∪ 𝐵) ∖ 𝐶) = ((𝐴 ∖ 𝐶) ∪ (𝐵 ∖ 𝐶)) | ||
Theorem | difindi 4281 | Distributive law for class difference. Theorem 40 of [Suppes] p. 29. (Contributed by NM, 17-Aug-2004.) |
⊢ (𝐴 ∖ (𝐵 ∩ 𝐶)) = ((𝐴 ∖ 𝐵) ∪ (𝐴 ∖ 𝐶)) | ||
Theorem | difindir 4282 | Distributive law for class difference. (Contributed by NM, 17-Aug-2004.) |
⊢ ((𝐴 ∩ 𝐵) ∖ 𝐶) = ((𝐴 ∖ 𝐶) ∩ (𝐵 ∖ 𝐶)) | ||
Theorem | indifdi 4283 | Distribute intersection over difference. (Contributed by BTernaryTau, 14-Aug-2024.) |
⊢ (𝐴 ∩ (𝐵 ∖ 𝐶)) = ((𝐴 ∩ 𝐵) ∖ (𝐴 ∩ 𝐶)) | ||
Theorem | indifdir 4284 | Distribute intersection over difference. (Contributed by Scott Fenton, 14-Apr-2011.) (Revised by BTernaryTau, 14-Aug-2024.) |
⊢ ((𝐴 ∖ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∖ (𝐵 ∩ 𝐶)) | ||
Theorem | indifdirOLD 4285 | Obsolete version of indifdir 4284 as of 14-Aug-2024. (Contributed by Scott Fenton, 14-Apr-2011.) (Proof modification is discouraged.) (New usage is discouraged.) |
⊢ ((𝐴 ∖ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∖ (𝐵 ∩ 𝐶)) | ||
Theorem | difdif2 4286 | Class difference by a class difference. (Contributed by Thierry Arnoux, 18-Dec-2017.) |
⊢ (𝐴 ∖ (𝐵 ∖ 𝐶)) = ((𝐴 ∖ 𝐵) ∪ (𝐴 ∩ 𝐶)) | ||
Theorem | undm 4287 | De Morgan's law for union. Theorem 5.2(13) of [Stoll] p. 19. (Contributed by NM, 18-Aug-2004.) |
⊢ (V ∖ (𝐴 ∪ 𝐵)) = ((V ∖ 𝐴) ∩ (V ∖ 𝐵)) | ||
Theorem | indm 4288 | De Morgan's law for intersection. Theorem 5.2(13') of [Stoll] p. 19. (Contributed by NM, 18-Aug-2004.) |
⊢ (V ∖ (𝐴 ∩ 𝐵)) = ((V ∖ 𝐴) ∪ (V ∖ 𝐵)) | ||
Theorem | difun1 4289 | A relationship involving double difference and union. (Contributed by NM, 29-Aug-2004.) |
⊢ (𝐴 ∖ (𝐵 ∪ 𝐶)) = ((𝐴 ∖ 𝐵) ∖ 𝐶) | ||
Theorem | undif3 4290 | An equality involving class union and class difference. The first equality of Exercise 13 of [TakeutiZaring] p. 22. (Contributed by Alan Sare, 17-Apr-2012.) (Proof shortened by JJ, 13-Jul-2021.) |
⊢ (𝐴 ∪ (𝐵 ∖ 𝐶)) = ((𝐴 ∪ 𝐵) ∖ (𝐶 ∖ 𝐴)) | ||
Theorem | difin2 4291 | Represent a class difference as an intersection with a larger difference. (Contributed by Jeff Madsen, 2-Sep-2009.) |
⊢ (𝐴 ⊆ 𝐶 → (𝐴 ∖ 𝐵) = ((𝐶 ∖ 𝐵) ∩ 𝐴)) | ||
Theorem | dif32 4292 | Swap second and third argument of double difference. (Contributed by NM, 18-Aug-2004.) |
⊢ ((𝐴 ∖ 𝐵) ∖ 𝐶) = ((𝐴 ∖ 𝐶) ∖ 𝐵) | ||
Theorem | difabs 4293 | Absorption-like law for class difference: you can remove a class only once. (Contributed by FL, 2-Aug-2009.) |
⊢ ((𝐴 ∖ 𝐵) ∖ 𝐵) = (𝐴 ∖ 𝐵) | ||
Theorem | sscon34b 4294 | Relative complementation reverses inclusion of subclasses. Relativized version of complss 4146. (Contributed by RP, 3-Jun-2021.) |
⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) → (𝐴 ⊆ 𝐵 ↔ (𝐶 ∖ 𝐵) ⊆ (𝐶 ∖ 𝐴))) | ||
Theorem | rcompleq 4295 | Two subclasses are equal if and only if their relative complements are equal. Relativized version of compleq 4147. (Contributed by RP, 10-Jun-2021.) |
⊢ ((𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐶) → (𝐴 = 𝐵 ↔ (𝐶 ∖ 𝐴) = (𝐶 ∖ 𝐵))) | ||
Theorem | dfsymdif3 4296 | Alternate definition of the symmetric difference, given in Example 4.1 of [Stoll] p. 262 (the original definition corresponds to [Stoll] p. 13). (Contributed by NM, 17-Aug-2004.) (Revised by BJ, 30-Apr-2020.) |
⊢ (𝐴 △ 𝐵) = ((𝐴 ∪ 𝐵) ∖ (𝐴 ∩ 𝐵)) | ||
Theorem | unabw 4297* | Union of two class abstractions. Version of unab 4298 using implicit substitution, which does not require ax-8 2109, ax-10 2138, ax-12 2172. (Contributed by Gino Giotto, 15-Oct-2024.) |
⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜒)) & ⊢ (𝑥 = 𝑦 → (𝜓 ↔ 𝜃)) ⇒ ⊢ ({𝑥 ∣ 𝜑} ∪ {𝑥 ∣ 𝜓}) = {𝑦 ∣ (𝜒 ∨ 𝜃)} | ||
Theorem | unab 4298 | Union of two class abstractions. (Contributed by NM, 29-Sep-2002.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ ({𝑥 ∣ 𝜑} ∪ {𝑥 ∣ 𝜓}) = {𝑥 ∣ (𝜑 ∨ 𝜓)} | ||
Theorem | inab 4299 | Intersection of two class abstractions. (Contributed by NM, 29-Sep-2002.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ ({𝑥 ∣ 𝜑} ∩ {𝑥 ∣ 𝜓}) = {𝑥 ∣ (𝜑 ∧ 𝜓)} | ||
Theorem | difab 4300 | Difference of two class abstractions. (Contributed by NM, 23-Oct-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) |
⊢ ({𝑥 ∣ 𝜑} ∖ {𝑥 ∣ 𝜓}) = {𝑥 ∣ (𝜑 ∧ ¬ 𝜓)} |
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