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Theorem inin 33166
Description: Intersection with an intersection. (Contributed by Thierry Arnoux, 27-Dec-2016.)
Assertion
Ref Expression
inin (𝐴 ∩ (𝐴 ∩ 𝐵)) = (𝐴 ∩ 𝐵)

Proof of Theorem inin
StepHypRef Expression
1 in13 4129 . 2 (𝐴 ∩ (𝐴 ∩ 𝐵)) = (𝐵 ∩ (𝐴 ∩ 𝐴))
2 inidm 4125 . . 3 (𝐴 ∩ 𝐴) = 𝐴
32ineq2i 4116 . 2 (𝐵 ∩ (𝐴 ∩ 𝐴)) = (𝐵 ∩ 𝐴)
4 incom 4108 . 2 (𝐵 ∩ 𝐴) = (𝐴 ∩ 𝐵)
51, 3, 43eqtri 2790 1 (𝐴 ∩ (𝐴 ∩ 𝐵)) = (𝐴 ∩ 𝐵)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   = wceq 1569   ∩ cin 4091
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1944  ax-6 2001  ax-7 2042  ax-8 2148  ax-9 2156  ax-ext 2735
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1572  df-ex 1812  df-sb 2101  df-clab 2742  df-cleq 2755  df-clel 2838  df-rab 3416  df-v 3455  df-in 4093
This theorem is used by:  measinb2  34909
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