| Mathbox for Peter Mazsa |
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| Mirrors > Home > MPE Home > Th. List > Mathboxes > qseq1i | Structured version Visualization version GIF version | ||
| Description: Equality theorem for quotient set, inference form. (Contributed by Peter Mazsa, 3-Jun-2021.) |
| Ref | Expression |
|---|---|
| qseq1i.1 | ⊢ 𝐴 = 𝐵 |
| Ref | Expression |
|---|---|
| qseq1i | ⊢ (𝐴 / 𝐶) = (𝐵 / 𝐶) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | qseq1i.1 | . 2 ⊢ 𝐴 = 𝐵 | |
| 2 | qseq1 8760 | . 2 ⊢ (𝐴 = 𝐵 → (𝐴 / 𝐶) = (𝐵 / 𝐶)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (𝐴 / 𝐶) = (𝐵 / 𝐶) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: = wceq 1570 / cqs 8699 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1943 ax-6 2000 ax-7 2041 ax-9 2156 ax-ext 2737 |
| This proof depends on definitions: df-bi 210 df-an 402 df-ex 1813 df-sb 2100 df-clab 2744 df-cleq 2757 df-rex 3092 df-qs 8706 |
| This theorem is used by: dmqscoelseq 39453 |
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