Theorem rbaibr 533

Description: Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.) (Proof shortened by Wolf Lammen, 19-Jan-2020.)

Hypothesis

Ref	Expression
baib.1	⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))

Assertion

Ref	Expression
rbaibr	⊢ (𝜒 → (𝜓 ↔ 𝜑))

Proof of Theorem rbaibr

Step	Hyp	Ref	Expression
1		iba 523	. 2 ⊢ (𝜒 → (𝜓 ↔ (𝜓 ∧ 𝜒)))
2		baib.1	. 2 ⊢ (𝜑 ↔ (𝜓 ∧ 𝜒))
3	1, 2	syl6bbr 281	1 ⊢ (𝜒 → (𝜓 ↔ 𝜑))

Syntax hints:   → wi 4   ↔ wb 198   ∧ wa 386

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 199  df-an 387

This theorem is referenced by:  rbaib  534  exintrbi  1937  moeuex  2602  sssseq  3839  ssunsn2  4589  cmpfi  21620  sdrgacs  38730  nanorxor  39460