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Theorem relpeq5 45640
Description: Equality theorem for relation-preserving functions. (Contributed by Eric Schmidt, 11-Oct-2025.)
Assertion
Ref Expression
relpeq5 (𝐵 = 𝐶 → (𝐻 RelPres 𝑅, 𝑆(𝐴, 𝐵) ↔ 𝐻 RelPres 𝑅, 𝑆(𝐴, 𝐶)))

Proof of Theorem relpeq5
Dummy variables 𝑥 𝑦 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 feq3 6687 . . 3 (𝐵 = 𝐶 → (𝐻:𝐴𝐵𝐻:𝐴𝐶))
21anbi1d 642 . 2 (𝐵 = 𝐶 → ((𝐻:𝐴𝐵 ∧ ∀𝑥𝐴𝑦𝐴 (𝑥𝑅𝑦 → (𝐻𝑥)𝑆(𝐻𝑦))) ↔ (𝐻:𝐴𝐶 ∧ ∀𝑥𝐴𝑦𝐴 (𝑥𝑅𝑦 → (𝐻𝑥)𝑆(𝐻𝑦)))))
3 df-relp 45635 . 2 (𝐻 RelPres 𝑅, 𝑆(𝐴, 𝐵) ↔ (𝐻:𝐴𝐵 ∧ ∀𝑥𝐴𝑦𝐴 (𝑥𝑅𝑦 → (𝐻𝑥)𝑆(𝐻𝑦))))
4 df-relp 45635 . 2 (𝐻 RelPres 𝑅, 𝑆(𝐴, 𝐶) ↔ (𝐻:𝐴𝐶 ∧ ∀𝑥𝐴𝑦𝐴 (𝑥𝑅𝑦 → (𝐻𝑥)𝑆(𝐻𝑦))))
52, 3, 43bitr4g 317 1 (𝐵 = 𝐶 → (𝐻 RelPres 𝑅, 𝑆(𝐴, 𝐵) ↔ 𝐻 RelPres 𝑅, 𝑆(𝐴, 𝐶)))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 209  wa 400   = wceq 1570  wral 3079   class class class wbr 5110  wf 6534  cfv 6538   RelPres wrelp 45634
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-9 2153  ax-ext 2735
This theorem depends on definitions:  df-bi 210  df-an 401  df-ex 1810  df-cleq 2755  df-ss 3923  df-f 6542  df-relp 45635
This theorem is referenced by: (None)
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