Theorem sprid 48256

Description: Two identical representations of the class of all unordered pairs. (Contributed by AV, 21-Nov-2021.)

Assertion

Ref	Expression
sprid	⊢ {𝑝 ∣ ∃𝑎 ∈ V ∃𝑏 ∈ V 𝑝 = {𝑎, 𝑏}} = {𝑝 ∣ ∃𝑎∃𝑏 𝑝 = {𝑎, 𝑏}}

Proof of Theorem sprid

Step	Hyp	Ref	Expression
1		rexv 3484	. . 3 ⊢ (∃𝑎 ∈ V ∃𝑏 ∈ V 𝑝 = {𝑎, 𝑏} ↔ ∃𝑎∃𝑏 ∈ V 𝑝 = {𝑎, 𝑏})
2		rexv 3484	. . . 4 ⊢ (∃𝑏 ∈ V 𝑝 = {𝑎, 𝑏} ↔ ∃𝑏 𝑝 = {𝑎, 𝑏})
3	2	exbii 1881	. . 3 ⊢ (∃𝑎∃𝑏 ∈ V 𝑝 = {𝑎, 𝑏} ↔ ∃𝑎∃𝑏 𝑝 = {𝑎, 𝑏})
4	1, 3	bitri 278	. 2 ⊢ (∃𝑎 ∈ V ∃𝑏 ∈ V 𝑝 = {𝑎, 𝑏} ↔ ∃𝑎∃𝑏 𝑝 = {𝑎, 𝑏})
5	4	abbii 2832	1 ⊢ {𝑝 ∣ ∃𝑎 ∈ V ∃𝑏 ∈ V 𝑝 = {𝑎, 𝑏}} = {𝑝 ∣ ∃𝑎∃𝑏 𝑝 = {𝑎, 𝑏}}

This proof depends on syntax axioms:   = wceq 1570  ∃wex 1812  {cab 2743  ∃wrex 3091  Vcvv 3457  {cpr 4593

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-ext 2737

This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2744  df-cleq 2757  df-clel 2840  df-rex 3092  df-v 3459

This theorem is used by: (None)