Theorem vjust 3458

Description: Justification theorem for df-v 3459. (Contributed by Rodolfo Medina, 27-Apr-2010.)

Assertion

Ref	Expression
vjust	⊢ {𝑥 ∣ 𝑥 = 𝑥} = {𝑦 ∣ 𝑦 = 𝑦}

Proof of Theorem vjust

Dummy variable 𝑧 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		equid 2045	. . . 4 ⊢ 𝑥 = 𝑥
2	1	vexw 2749	. . 3 ⊢ 𝑧 ∈ {𝑥 ∣ 𝑥 = 𝑥}
3		equid 2045	. . . 4 ⊢ 𝑦 = 𝑦
4	3	vexw 2749	. . 3 ⊢ 𝑧 ∈ {𝑦 ∣ 𝑦 = 𝑦}
5	2, 4	2th 267	. 2 ⊢ (𝑧 ∈ {𝑥 ∣ 𝑥 = 𝑥} ↔ 𝑧 ∈ {𝑦 ∣ 𝑦 = 𝑦})
6	5	eqriv 2762	1 ⊢ {𝑥 ∣ 𝑥 = 𝑥} = {𝑦 ∣ 𝑦 = 𝑦}

This proof depends on syntax axioms:   = wceq 1570   ∈ wcel 2146  {cab 2743

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-9 2156  ax-ext 2737

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-sb 2100  df-clab 2744  df-cleq 2757

This theorem is used by: (None)