Theorem neeq1i 2375

Description: Inference for inequality. (Contributed by NM, 29-Apr-2005.)

Hypothesis

Ref	Expression
neeq1i.1	|- A = B

Assertion

Ref	Expression
neeq1i	|- ( A =/= C <-> B =/= C )

Proof of Theorem neeq1i

Step	Hyp	Ref	Expression
1		neeq1i.1	. 2 |- A = B
2		neeq1 2373	. 2 |- ( A = B -> ( A =/= C <-> B =/= C ) )
3	1, 2	ax-mp 5	1 |- ( A =/= C <-> B =/= C )

Syntax hints:   <-> wb 105   = wceq 1364   =/= wne 2360

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-5 1458  ax-gen 1460  ax-4 1521  ax-17 1537  ax-ext 2171

This theorem depends on definitions:  df-bi 117  df-cleq 2182  df-ne 2361

This theorem is referenced by:  neeq12i  2377  eqnetri  2383  eqnetrrid  2391  rabn0r  3464