Theorem preq2d 3775

Description: Equality deduction for unordered pairs. (Contributed by NM, 19-Oct-2012.)

Hypothesis

Ref	Expression
preq1d.1	|- ( ph -> A = B )

Assertion

Ref	Expression
preq2d	|- ( ph -> { C , A } = { C , B } )

Proof of Theorem preq2d

Step	Hyp	Ref	Expression
1		preq1d.1	. 2 |- ( ph -> A = B )
2		preq2 3769	. 2 |- ( A = B -> { C , A } = { C , B } )
3	1, 2	syl 14	1 |- ( ph -> { C , A } = { C , B } )

Syntax hints:   -> wi 4   = wceq 1398   {cpr 3690

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2214

This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1812  df-clab 2219  df-cleq 2225  df-clel 2228  df-nfc 2373  df-v 2815  df-un 3215  df-sn 3695  df-pr 3696

This theorem is referenced by:  opthreg  4678  funopsn  5860  hashtpglem  11218  prdsex  13482  gsumprval  13612  clwwlkn2  16416  clwwlknonex2lem1  16432  eupth2lem3lem3fi  16465  eupth2fi  16474