Theorem sbhb 1911

Description: Two ways of expressing " x is (effectively) not free in ph." (Contributed by NM, 29-May-2009.)

Assertion

Ref	Expression
sbhb	|- ( ( ph -> A. x ph ) <-> A. y ( ph -> [ y / x ] ph ) )

Distinct variable group:   ph, y

Allowed substitution hint:   ph( x)

Proof of Theorem sbhb

Step	Hyp	Ref	Expression
1		ax-17 1506	. . . 4 |- ( ph -> A. y ph )
2	1	sb8h 1826	. . 3 |- ( A. x ph <-> A. y [ y / x ] ph )
3	2	imbi2i 225	. 2 |- ( ( ph -> A. x ph ) <-> ( ph -> A. y [ y / x ] ph ) )
4		19.21v 1845	. 2 |- ( A. y ( ph -> [ y / x ] ph ) <-> ( ph -> A. y [ y / x ] ph ) )
5	3, 4	bitr4i 186	1 |- ( ( ph -> A. x ph ) <-> A. y ( ph -> [ y / x ] ph ) )

Syntax hints:   -> wi 4   <-> wb 104   A.wal 1329   [wsb 1735

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1423  ax-7 1424  ax-gen 1425  ax-ie1 1469  ax-ie2 1470  ax-8 1482  ax-11 1484  ax-4 1487  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515

This theorem depends on definitions:  df-bi 116  df-nf 1437  df-sb 1736

This theorem is referenced by:  sbnf2  1954