Theorem dfss 3182

Description: Variant of subclass definition df-ss 3181. (Contributed by NM, 3-Sep-2004.)

Assertion

Ref	Expression
dfss	⊢ (𝐴 ⊆ 𝐵 ↔ 𝐴 = (𝐴 ∩ 𝐵))

Proof of Theorem dfss

Step	Hyp	Ref	Expression
1		df-ss 3181	. 2 ⊢ (𝐴 ⊆ 𝐵 ↔ (𝐴 ∩ 𝐵) = 𝐴)
2		eqcom 2208	. 2 ⊢ ((𝐴 ∩ 𝐵) = 𝐴 ↔ 𝐴 = (𝐴 ∩ 𝐵))
3	1, 2	bitri 184	1 ⊢ (𝐴 ⊆ 𝐵 ↔ 𝐴 = (𝐴 ∩ 𝐵))

Syntax hints:   ↔ wb 105   = wceq 1373   ∩ cin 3167   ⊆ wss 3168

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1471  ax-gen 1473  ax-ext 2188

This theorem depends on definitions:  df-bi 117  df-cleq 2199  df-ss 3181

This theorem is referenced by:  ssalel  3183  onelini  4482  cnvcnv  5141  funimass1  5357  sbthlemi5  7075  dmaddpi  7451  dmmulpi  7452  tgioo  15076