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Theorem errel 6706
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 6697 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1036 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1395  cun 3196  wss 3198  ccnv 4722  dom cdm 4723  ccom 4727  Rel wrel 4728   Er wer 6694
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106
This theorem depends on definitions:  df-bi 117  df-3an 1004  df-er 6697
This theorem is referenced by:  ercl  6708  ersym  6709  ertr  6712  ercnv  6718  erssxp  6720  erth  6743  iinerm  6771  eqg0el  13809
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