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Theorem errel 6702
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 6693 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1036 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1395  cun 3195  wss 3197  ccnv 4719  dom cdm 4720  ccom 4724  Rel wrel 4725   Er wer 6690
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106
This theorem depends on definitions:  df-bi 117  df-3an 1004  df-er 6693
This theorem is referenced by:  ercl  6704  ersym  6705  ertr  6708  ercnv  6714  erssxp  6716  erth  6739  iinerm  6767  eqg0el  13787
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