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Theorem errel 6641
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 6632 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1015 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1373  cun 3168  wss 3170  ccnv 4681  dom cdm 4682  ccom 4686  Rel wrel 4687   Er wer 6629
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106
This theorem depends on definitions:  df-bi 117  df-3an 983  df-er 6632
This theorem is referenced by:  ercl  6643  ersym  6644  ertr  6647  ercnv  6653  erssxp  6655  erth  6678  iinerm  6706  eqg0el  13635
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