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Theorem errel 6775
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 6766 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1039 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1398  cun 3208  wss 3210  ccnv 4747  dom cdm 4748  ccom 4752  Rel wrel 4753   Er wer 6763
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106
This theorem depends on definitions:  df-bi 117  df-3an 1007  df-er 6766
This theorem is referenced by:  ercl  6777  ersym  6778  ertr  6781  ercnv  6787  erssxp  6789  erth  6812  iinerm  6840  eqg0el  13938
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