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Theorem errel 6789
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 6780 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1039 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1398  cun 3212  wss 3214  ccnv 4753  dom cdm 4754  ccom 4758  Rel wrel 4759   Er wer 6777
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106
This theorem depends on definitions:  df-bi 117  df-3an 1007  df-er 6780
This theorem is referenced by:  ercl  6791  ersym  6792  ertr  6795  ercnv  6801  erssxp  6803  erth  6826  iinerm  6854  eqg0el  14030
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