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Theorem errel 6816
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 6807 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (◡𝑅 ∪ (𝑅 ∘ 𝑅)) ⊆ 𝑅))
21simp1bi 1043 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables:    wff set class
This proof depends on syntax axioms:   → wi 4   = wceq 1402   ∪ cun 3218   ⊆ wss 3220  ◡ccnv 4773  dom cdm 4774   ∘ ccom 4778  Rel wrel 4779   Er wer 6804
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106
This proof depends on definitions:  df-bi 117  df-3an 1011  df-er 6807
This theorem is used by:  ercl  6818  ersym  6819  ertr  6822  ercnv  6828  erssxp  6830  erth  6853  iinerm  6881  eqg0el  14085
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