Theorem imdistanda 452

Description: Distribution of implication with conjunction (deduction version with conjoined antecedent). (Contributed by Jeff Madsen, 19-Jun-2011.)

Hypothesis

Ref	Expression
imdistanda.1	⊢ ((𝜑 ∧ 𝜓) → (𝜒 → 𝜃))

Assertion

Ref	Expression
imdistanda	⊢ (𝜑 → ((𝜓 ∧ 𝜒) → (𝜓 ∧ 𝜃)))

Proof of Theorem imdistanda

Step	Hyp	Ref	Expression
1		imdistanda.1	. . 3 ⊢ ((𝜑 ∧ 𝜓) → (𝜒 → 𝜃))
2	1	ex 115	. 2 ⊢ (𝜑 → (𝜓 → (𝜒 → 𝜃)))
3	2	imdistand 451	1 ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → (𝜓 ∧ 𝜃)))

This proof depends on syntax axioms:   → wi 4   ∧ wa 104

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This proof depends on definitions:  df-bi 117

This theorem is used by:  fzind  9766  uzss  9953  exbtwnzlemshrink  10694  rebtwn2zlemshrink  10699  cau3lem  11897  dvdsrvald  14484  dvdsrex  14489  iscnp4  15410  cnntr  15417