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Theorem pm2.21ddne 2503
Description: A contradiction implies anything. Equality/inequality deduction form. (Contributed by David Moews, 28-Feb-2017.)
Hypotheses
Ref Expression
pm2.21ddne.1 (𝜑 → 𝐴 = 𝐵)
pm2.21ddne.2 (𝜑 → 𝐴 ≠ 𝐵)
Assertion
Ref Expression
pm2.21ddne (𝜑 → 𝜓)

Proof of Theorem pm2.21ddne
StepHypRef Expression
1 pm2.21ddne.1 . 2 (𝜑 → 𝐴 = 𝐵)
2 pm2.21ddne.2 . . 3 (𝜑 → 𝐴 ≠ 𝐵)
32neneqd 2441 . 2 (𝜑 → ¬ 𝐴 = 𝐵)
41, 3pm2.21dd 629 1 (𝜑 → 𝜓)
Colors of variables:    wff set class
This proof depends on syntax axioms:   → wi 4   = wceq 1402   ≠ wne 2420
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-in2 624
This proof depends on definitions:  df-bi 117  df-ne 2421
This theorem is used by:  npnflt  10228  nmnfgt  10231  xlt2add  10293  xrbdtri  12061  divalglemex  12708  divalg  12710  znege1  12977  ennnfonelemex  13357  pw1ndom3  17191
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