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Theorem an42 670
Description: Rearrangement of 4 conjuncts. (Contributed by NM, 7-Feb-1996.)
Assertion
Ref Expression
an42 (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜒) ∧ (𝜃 ∧ 𝜓)))

Proof of Theorem an42
StepHypRef Expression
1 an4 669 . 2 (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜒) ∧ (𝜓 ∧ 𝜃)))
2 ancom 466 . . 3 ((𝜓 ∧ 𝜃) ↔ (𝜃 ∧ 𝜓))
32anbi2i 635 . 2 (((𝜑 ∧ 𝜒) ∧ (𝜓 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜒) ∧ (𝜃 ∧ 𝜓)))
41, 3bitri 278 1 (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜒) ∧ (𝜃 ∧ 𝜓)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402
This theorem is used by:  an43  671  4anpull2  1382  an33rean  1514  brecop2  8832  supmo  9444  infmo  9489  aceq1  10196  dfiso2  17947  eulerpartlemt0  35001  isbasisrelowllem1  38278  isbasisrelowllem2  38279  ifp1bi  44502
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