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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | sylan2br 601 | A syllogism inference. (Contributed by NM, 21-Apr-1994.) |
| ⊢ (𝜒 ↔ 𝜑) & ⊢ ((𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜓 ∧ 𝜑) → 𝜃) | ||
| Theorem | syl2an 602 | A double syllogism inference. For an implication-only version, see syl2im 40. (Contributed by NM, 31-Jan-1997.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜏 → 𝜒) & ⊢ ((𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜏) → 𝜃) | ||
| Theorem | syl2anr 603 | A double syllogism inference. For an implication-only version, see syl2imc 41. (Contributed by NM, 17-Sep-2013.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜏 → 𝜒) & ⊢ ((𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜏 ∧ 𝜑) → 𝜃) | ||
| Theorem | syl2anb 604 | A double syllogism inference. (Contributed by NM, 29-Jul-1999.) |
| ⊢ (𝜑 ↔ 𝜓) & ⊢ (𝜏 ↔ 𝜒) & ⊢ ((𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜏) → 𝜃) | ||
| Theorem | syl2anbr 605 | A double syllogism inference. (Contributed by NM, 29-Jul-1999.) |
| ⊢ (𝜓 ↔ 𝜑) & ⊢ (𝜒 ↔ 𝜏) & ⊢ ((𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜏) → 𝜃) | ||
| Theorem | sylancb 606 | A syllogism inference combined with contraction. (Contributed by NM, 3-Sep-2004.) |
| ⊢ (𝜑 ↔ 𝜓) & ⊢ (𝜑 ↔ 𝜒) & ⊢ ((𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ (𝜑 → 𝜃) | ||
| Theorem | sylancbr 607 | A syllogism inference combined with contraction. (Contributed by NM, 3-Sep-2004.) |
| ⊢ (𝜓 ↔ 𝜑) & ⊢ (𝜒 ↔ 𝜑) & ⊢ ((𝜓 ∧ 𝜒) → 𝜃) ⇒ ⊢ (𝜑 → 𝜃) | ||
| Theorem | syldanl 608 | A syllogism deduction with conjoined antecedents. (Contributed by Jeff Madsen, 20-Jun-2011.) |
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ (((𝜑 ∧ 𝜒) ∧ 𝜃) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜃) → 𝜏) | ||
| Theorem | syland 609 | A syllogism deduction. (Contributed by NM, 15-Dec-2004.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜑 → ((𝜒 ∧ 𝜃) → 𝜏)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃) → 𝜏)) | ||
| Theorem | sylani 610 | A syllogism inference. (Contributed by NM, 2-May-1996.) |
| ⊢ (𝜑 → 𝜒) & ⊢ (𝜓 → ((𝜒 ∧ 𝜃) → 𝜏)) ⇒ ⊢ (𝜓 → ((𝜑 ∧ 𝜃) → 𝜏)) | ||
| Theorem | sylan2d 611 | A syllogism deduction. (Contributed by NM, 15-Dec-2004.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜑 → ((𝜃 ∧ 𝜒) → 𝜏)) ⇒ ⊢ (𝜑 → ((𝜃 ∧ 𝜓) → 𝜏)) | ||
| Theorem | sylan2i 612 | A syllogism inference. (Contributed by NM, 1-Aug-1994.) |
| ⊢ (𝜑 → 𝜃) & ⊢ (𝜓 → ((𝜒 ∧ 𝜃) → 𝜏)) ⇒ ⊢ (𝜓 → ((𝜒 ∧ 𝜑) → 𝜏)) | ||
| Theorem | syl2ani 613 | A syllogism inference. (Contributed by NM, 3-Aug-1999.) |
| ⊢ (𝜑 → 𝜒) & ⊢ (𝜂 → 𝜃) & ⊢ (𝜓 → ((𝜒 ∧ 𝜃) → 𝜏)) ⇒ ⊢ (𝜓 → ((𝜑 ∧ 𝜂) → 𝜏)) | ||
| Theorem | syl2and 614 | A syllogism deduction. (Contributed by NM, 15-Dec-2004.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜑 → (𝜃 → 𝜏)) & ⊢ (𝜑 → ((𝜒 ∧ 𝜏) → 𝜂)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃) → 𝜂)) | ||
| Theorem | anim12d 615 | Conjoin antecedents and consequents in a deduction. (Contributed by NM, 3-Apr-1994.) (Proof shortened by Wolf Lammen, 18-Dec-2013.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜑 → (𝜃 → 𝜏)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃) → (𝜒 ∧ 𝜏))) | ||
| Theorem | anim12d1 616 | Variant of anim12d 615 where the second implication does not depend on the antecedent. (Contributed by Rodolfo Medina, 12-Oct-2010.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜃 → 𝜏) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃) → (𝜒 ∧ 𝜏))) | ||
| Theorem | anim1d 617 | Add a conjunct to right of antecedent and consequent in a deduction. (Contributed by NM, 3-Apr-1994.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃) → (𝜒 ∧ 𝜃))) | ||
| Theorem | anim2d 618 | Add a conjunct to left of antecedent and consequent in a deduction. (Contributed by NM, 14-May-1993.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) ⇒ ⊢ (𝜑 → ((𝜃 ∧ 𝜓) → (𝜃 ∧ 𝜒))) | ||
| Theorem | anim12i 619 | Conjoin antecedents and consequents of two premises. (Contributed by NM, 3-Jan-1993.) (Proof shortened by Wolf Lammen, 14-Dec-2013.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜒 → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒) → (𝜓 ∧ 𝜃)) | ||
| Theorem | anim12ci 620 | Variant of anim12i 619 with commutation. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜒 → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒) → (𝜃 ∧ 𝜓)) | ||
| Theorem | anim1i 621 | Introduce conjunct to both sides of an implication. (Contributed by NM, 5-Aug-1993.) |
| ⊢ (𝜑 → 𝜓) ⇒ ⊢ ((𝜑 ∧ 𝜒) → (𝜓 ∧ 𝜒)) | ||
| Theorem | anim1ci 622 | Introduce conjunct to both sides of an implication. (Contributed by Peter Mazsa, 24-Sep-2022.) |
| ⊢ (𝜑 → 𝜓) ⇒ ⊢ ((𝜑 ∧ 𝜒) → (𝜒 ∧ 𝜓)) | ||
| Theorem | anim2i 623 | Introduce conjunct to both sides of an implication. (Contributed by NM, 3-Jan-1993.) |
| ⊢ (𝜑 → 𝜓) ⇒ ⊢ ((𝜒 ∧ 𝜑) → (𝜒 ∧ 𝜓)) | ||
| Theorem | anim12ii 624 | Conjoin antecedents and consequents in a deduction. (Contributed by NM, 11-Nov-2007.) (Proof shortened by Wolf Lammen, 19-Jul-2013.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜃 → (𝜓 → 𝜏)) ⇒ ⊢ ((𝜑 ∧ 𝜃) → (𝜓 → (𝜒 ∧ 𝜏))) | ||
| Theorem | anim12dan 625 | Conjoin antecedents and consequents in a deduction. (Contributed by Jeff Madsen, 16-Jun-2011.) |
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ ((𝜑 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜃)) → (𝜒 ∧ 𝜏)) | ||
| Theorem | im2anan9 626 | Deduction joining nested implications to form implication of conjunctions. (Contributed by NM, 29-Feb-1996.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜃 → (𝜏 → 𝜂)) ⇒ ⊢ ((𝜑 ∧ 𝜃) → ((𝜓 ∧ 𝜏) → (𝜒 ∧ 𝜂))) | ||
| Theorem | im2anan9r 627 | Deduction joining nested implications to form implication of conjunctions. (Contributed by NM, 29-Feb-1996.) |
| ⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜃 → (𝜏 → 𝜂)) ⇒ ⊢ ((𝜃 ∧ 𝜑) → ((𝜓 ∧ 𝜏) → (𝜒 ∧ 𝜂))) | ||
| Theorem | pm3.45 628 | Theorem *3.45 (Fact) of [WhiteheadRussell] p. 113. (Contributed by NM, 3-Jan-2005.) |
| ⊢ ((𝜑 → 𝜓) → ((𝜑 ∧ 𝜒) → (𝜓 ∧ 𝜒))) | ||
| Theorem | anbi2i 629 | Introduce a left conjunct to both sides of a logical equivalence. (Contributed by NM, 3-Jan-1993.) (Proof shortened by Wolf Lammen, 16-Nov-2013.) |
| ⊢ (𝜑 ↔ 𝜓) ⇒ ⊢ ((𝜒 ∧ 𝜑) ↔ (𝜒 ∧ 𝜓)) | ||
| Theorem | anbi1i 630 | Introduce a right conjunct to both sides of a logical equivalence. (Contributed by NM, 12-Mar-1993.) (Proof shortened by Wolf Lammen, 16-Nov-2013.) |
| ⊢ (𝜑 ↔ 𝜓) ⇒ ⊢ ((𝜑 ∧ 𝜒) ↔ (𝜓 ∧ 𝜒)) | ||
| Theorem | anbi2ci 631 | Variant of anbi2i 629 with commutation. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) (Proof shortened by Andrew Salmon, 14-Jun-2011.) |
| ⊢ (𝜑 ↔ 𝜓) ⇒ ⊢ ((𝜑 ∧ 𝜒) ↔ (𝜒 ∧ 𝜓)) | ||
| Theorem | anbi1ci 632 | Variant of anbi1i 630 with commutation. (Contributed by Peter Mazsa, 7-Mar-2020.) |
| ⊢ (𝜑 ↔ 𝜓) ⇒ ⊢ ((𝜒 ∧ 𝜑) ↔ (𝜓 ∧ 𝜒)) | ||
| Theorem | bianbi 633 | Exchanging conjunction in a biconditional. (Contributed by Peter Mazsa, 31-Jul-2023.) |
| ⊢ (𝜑 ↔ (𝜓 ∧ 𝜒)) & ⊢ (𝜓 ↔ 𝜃) ⇒ ⊢ (𝜑 ↔ (𝜃 ∧ 𝜒)) | ||
| Theorem | anbi12i 634 | Conjoin both sides of two equivalences. (Contributed by NM, 12-Mar-1993.) |
| ⊢ (𝜑 ↔ 𝜓) & ⊢ (𝜒 ↔ 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒) ↔ (𝜓 ∧ 𝜃)) | ||
| Theorem | anbi12ci 635 | Variant of anbi12i 634 with commutation. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
| ⊢ (𝜑 ↔ 𝜓) & ⊢ (𝜒 ↔ 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒) ↔ (𝜃 ∧ 𝜓)) | ||
| Theorem | anbi2d 636 | Deduction adding a left conjunct to both sides of a logical equivalence. (Contributed by NM, 11-May-1993.) (Proof shortened by Wolf Lammen, 16-Nov-2013.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜃 ∧ 𝜓) ↔ (𝜃 ∧ 𝜒))) | ||
| Theorem | anbi1d 637 | Deduction adding a right conjunct to both sides of a logical equivalence. (Contributed by NM, 11-May-1993.) (Proof shortened by Wolf Lammen, 16-Nov-2013.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃) ↔ (𝜒 ∧ 𝜃))) | ||
| Theorem | anbi12d 638 | Deduction joining two equivalences to form equivalence of conjunctions. (Contributed by NM, 26-May-1993.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜑 → (𝜃 ↔ 𝜏)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃) ↔ (𝜒 ∧ 𝜏))) | ||
| Theorem | anbi1 639 | Introduce a right conjunct to both sides of a logical equivalence. Theorem *4.36 of [WhiteheadRussell] p. 118. (Contributed by NM, 3-Jan-2005.) |
| ⊢ ((𝜑 ↔ 𝜓) → ((𝜑 ∧ 𝜒) ↔ (𝜓 ∧ 𝜒))) | ||
| Theorem | anbi2 640 | Introduce a left conjunct to both sides of a logical equivalence. (Contributed by NM, 16-Nov-2013.) |
| ⊢ ((𝜑 ↔ 𝜓) → ((𝜒 ∧ 𝜑) ↔ (𝜒 ∧ 𝜓))) | ||
| Theorem | anbi1cd 641 | Introduce a proposition as left conjunct on the left-hand side and right conjunct on the right-hand side of an equivalence. Deduction form. (Contributed by Peter Mazsa, 22-May-2021.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜃 ∧ 𝜓) ↔ (𝜒 ∧ 𝜃))) | ||
| Theorem | an2anr 642 | Double commutation in conjunction. (Contributed by Peter Mazsa, 27-Jun-2019.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜓 ∧ 𝜑) ∧ (𝜃 ∧ 𝜒))) | ||
| Theorem | pm4.38 643 | Theorem *4.38 of [WhiteheadRussell] p. 118. (Contributed by NM, 3-Jan-2005.) |
| ⊢ (((𝜑 ↔ 𝜒) ∧ (𝜓 ↔ 𝜃)) → ((𝜑 ∧ 𝜓) ↔ (𝜒 ∧ 𝜃))) | ||
| Theorem | bi2anan9 644 | Deduction joining two equivalences to form equivalence of conjunctions. (Contributed by NM, 31-Jul-1995.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜃 → (𝜏 ↔ 𝜂)) ⇒ ⊢ ((𝜑 ∧ 𝜃) → ((𝜓 ∧ 𝜏) ↔ (𝜒 ∧ 𝜂))) | ||
| Theorem | bi2anan9r 645 | Deduction joining two equivalences to form equivalence of conjunctions. (Contributed by NM, 19-Feb-1996.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜃 → (𝜏 ↔ 𝜂)) ⇒ ⊢ ((𝜃 ∧ 𝜑) → ((𝜓 ∧ 𝜏) ↔ (𝜒 ∧ 𝜂))) | ||
| Theorem | bi2bian9 646 | Deduction joining two biconditionals with different antecedents. (Contributed by NM, 12-May-2004.) |
| ⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜃 → (𝜏 ↔ 𝜂)) ⇒ ⊢ ((𝜑 ∧ 𝜃) → ((𝜓 ↔ 𝜏) ↔ (𝜒 ↔ 𝜂))) | ||
| Theorem | anbiim 647 | Adding biconditional when antecedents are conjuncted. (Contributed by metakunt, 16-Apr-2024.) (Proof shortened by Wolf Lammen, 7-May-2025.) |
| ⊢ (𝜑 → (𝜒 → 𝜃)) & ⊢ (𝜓 → (𝜃 → 𝜒)) ⇒ ⊢ ((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃)) | ||
| Theorem | bianass 648 | An inference to merge two lists of conjuncts. (Contributed by Giovanni Mascellani, 23-May-2019.) |
| ⊢ (𝜑 ↔ (𝜓 ∧ 𝜒)) ⇒ ⊢ ((𝜂 ∧ 𝜑) ↔ ((𝜂 ∧ 𝜓) ∧ 𝜒)) | ||
| Theorem | bianassc 649 | An inference to merge two lists of conjuncts. (Contributed by Peter Mazsa, 24-Sep-2022.) |
| ⊢ (𝜑 ↔ (𝜓 ∧ 𝜒)) ⇒ ⊢ ((𝜂 ∧ 𝜑) ↔ ((𝜓 ∧ 𝜂) ∧ 𝜒)) | ||
| Theorem | an21 650 | Swap two conjuncts. (Contributed by Peter Mazsa, 18-Sep-2022.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒))) | ||
| Theorem | an12 651 | Swap two conjuncts. Note that the first digit (1) in the label refers to the outer conjunct position, and the next digit (2) to the inner conjunct position. (Contributed by NM, 12-Mar-1995.) (Proof shortened by Peter Mazsa, 18-Sep-2022.) |
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒))) | ||
| Theorem | an32 652 | A rearrangement of conjuncts. (Contributed by NM, 12-Mar-1995.) (Proof shortened by Wolf Lammen, 25-Dec-2012.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ((𝜑 ∧ 𝜒) ∧ 𝜓)) | ||
| Theorem | an13 653 | A rearrangement of conjuncts. (Contributed by NM, 24-Jun-2012.) (Proof shortened by Wolf Lammen, 31-Dec-2012.) |
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) ↔ (𝜒 ∧ (𝜓 ∧ 𝜑))) | ||
| Theorem | an31 654 | A rearrangement of conjuncts. (Contributed by NM, 24-Jun-2012.) (Proof shortened by Wolf Lammen, 31-Dec-2012.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ((𝜒 ∧ 𝜓) ∧ 𝜑)) | ||
| Theorem | an12s 655 | Swap two conjuncts in antecedent. The label suffix "s" means that an12 651 is combined with syl 17 (or a variant). (Contributed by NM, 13-Mar-1996.) |
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜓 ∧ (𝜑 ∧ 𝜒)) → 𝜃) | ||
| Theorem | ancom2s 656 | Inference commuting a nested conjunction in antecedent. (Contributed by NM, 24-May-2006.) (Proof shortened by Wolf Lammen, 24-Nov-2012.) |
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜑 ∧ (𝜒 ∧ 𝜓)) → 𝜃) | ||
| Theorem | an13s 657 | Swap two conjuncts in antecedent. (Contributed by NM, 31-May-2006.) |
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜒 ∧ (𝜓 ∧ 𝜑)) → 𝜃) | ||
| Theorem | an32s 658 | Swap two conjuncts in antecedent. (Contributed by NM, 13-Mar-1996.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ (((𝜑 ∧ 𝜒) ∧ 𝜓) → 𝜃) | ||
| Theorem | ancom1s 659 | Inference commuting a nested conjunction in antecedent. (Contributed by NM, 24-May-2006.) (Proof shortened by Wolf Lammen, 24-Nov-2012.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ (((𝜓 ∧ 𝜑) ∧ 𝜒) → 𝜃) | ||
| Theorem | an31s 660 | Swap two conjuncts in antecedent. (Contributed by NM, 31-May-2006.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ (((𝜒 ∧ 𝜓) ∧ 𝜑) → 𝜃) | ||
| Theorem | anass1rs 661 | Commutative-associative law for conjunction in an antecedent. (Contributed by Jeff Madsen, 19-Jun-2011.) |
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ (((𝜑 ∧ 𝜒) ∧ 𝜓) → 𝜃) | ||
| Theorem | an4 662 | Rearrangement of 4 conjuncts. (Contributed by NM, 10-Jul-1994.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜒) ∧ (𝜓 ∧ 𝜃))) | ||
| Theorem | an42 663 | Rearrangement of 4 conjuncts. (Contributed by NM, 7-Feb-1996.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜒) ∧ (𝜃 ∧ 𝜓))) | ||
| Theorem | an43 664 | Rearrangement of 4 conjuncts. (Contributed by Rodolfo Medina, 24-Sep-2010.) (Proof shortened by Andrew Salmon, 29-Jun-2011.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜒))) | ||
| Theorem | an3 665 | A rearrangement of conjuncts. (Contributed by Rodolfo Medina, 25-Sep-2010.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) → (𝜑 ∧ 𝜃)) | ||
| Theorem | an4s 666 | Inference rearranging 4 conjuncts in antecedent. (Contributed by NM, 10-Aug-1995.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜒) ∧ (𝜓 ∧ 𝜃)) → 𝜏) | ||
| Theorem | an42s 667 | Inference rearranging 4 conjuncts in antecedent. (Contributed by NM, 10-Aug-1995.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜒) ∧ (𝜃 ∧ 𝜓)) → 𝜏) | ||
| Theorem | anabs1 668 | Absorption into embedded conjunct. (Contributed by NM, 4-Sep-1995.) (Proof shortened by Wolf Lammen, 16-Nov-2013.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜑) ↔ (𝜑 ∧ 𝜓)) | ||
| Theorem | anabs5 669 | Absorption into embedded conjunct. (Contributed by NM, 20-Jul-1996.) (Proof shortened by Wolf Lammen, 9-Dec-2012.) |
| ⊢ ((𝜑 ∧ (𝜑 ∧ 𝜓)) ↔ (𝜑 ∧ 𝜓)) | ||
| Theorem | anabs7 670 | Absorption into embedded conjunct. (Contributed by NM, 20-Jul-1996.) (Proof shortened by Wolf Lammen, 17-Nov-2013.) |
| ⊢ ((𝜓 ∧ (𝜑 ∧ 𝜓)) ↔ (𝜑 ∧ 𝜓)) | ||
| Theorem | anabsan 671 | Absorption of antecedent with conjunction. (Contributed by NM, 24-Mar-1996.) |
| ⊢ (((𝜑 ∧ 𝜑) ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabss1 672 | Absorption of antecedent into conjunction. (Contributed by NM, 20-Jul-1996.) (Proof shortened by Wolf Lammen, 31-Dec-2012.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜑) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabss4 673 | Absorption of antecedent into conjunction. (Contributed by NM, 20-Jul-1996.) |
| ⊢ (((𝜓 ∧ 𝜑) ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabss5 674 | Absorption of antecedent into conjunction. (Contributed by NM, 10-May-1994.) (Proof shortened by Wolf Lammen, 1-Jan-2013.) |
| ⊢ ((𝜑 ∧ (𝜑 ∧ 𝜓)) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabsi5 675 | Absorption of antecedent into conjunction. (Contributed by NM, 11-Jun-1995.) (Proof shortened by Wolf Lammen, 18-Nov-2013.) |
| ⊢ (𝜑 → ((𝜑 ∧ 𝜓) → 𝜒)) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabsi6 676 | Absorption of antecedent into conjunction. (Contributed by NM, 14-Aug-2000.) |
| ⊢ (𝜑 → ((𝜓 ∧ 𝜑) → 𝜒)) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabsi7 677 | Absorption of antecedent into conjunction. (Contributed by NM, 20-Jul-1996.) (Proof shortened by Wolf Lammen, 18-Nov-2013.) |
| ⊢ (𝜓 → ((𝜑 ∧ 𝜓) → 𝜒)) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabsi8 678 | Absorption of antecedent into conjunction. (Contributed by NM, 26-Sep-1999.) |
| ⊢ (𝜓 → ((𝜓 ∧ 𝜑) → 𝜒)) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabss7 679 | Absorption of antecedent into conjunction. (Contributed by NM, 20-Jul-1996.) (Proof shortened by Wolf Lammen, 19-Nov-2013.) |
| ⊢ ((𝜓 ∧ (𝜑 ∧ 𝜓)) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabsan2 680 | Absorption of antecedent with conjunction. (Contributed by NM, 10-May-2004.) |
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜓)) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anabss3 681 | Absorption of antecedent into conjunction. (Contributed by NM, 20-Jul-1996.) (Proof shortened by Wolf Lammen, 1-Jan-2013.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜒) | ||
| Theorem | anandi 682 | Distribution of conjunction over conjunction. (Contributed by NM, 14-Aug-1995.) |
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) ↔ ((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒))) | ||
| Theorem | anandir 683 | Distribution of conjunction over conjunction. (Contributed by NM, 24-Aug-1995.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) ↔ ((𝜑 ∧ 𝜒) ∧ (𝜓 ∧ 𝜒))) | ||
| Theorem | anandis 684 | Inference that undistributes conjunction in the antecedent. (Contributed by NM, 7-Jun-2004.) |
| ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒)) → 𝜏) ⇒ ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜏) | ||
| Theorem | anandirs 685 | Inference that undistributes conjunction in the antecedent. (Contributed by NM, 7-Jun-2004.) |
| ⊢ (((𝜑 ∧ 𝜒) ∧ (𝜓 ∧ 𝜒)) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜏) | ||
| Theorem | sylanl1 686 | A syllogism inference. (Contributed by NM, 10-Mar-2005.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (((𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜒) ∧ 𝜃) → 𝜏) | ||
| Theorem | sylanl2 687 | A syllogism inference. (Contributed by NM, 1-Jan-2005.) |
| ⊢ (𝜑 → 𝜒) & ⊢ (((𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜏) ⇒ ⊢ (((𝜓 ∧ 𝜑) ∧ 𝜃) → 𝜏) | ||
| Theorem | sylanr1 688 | A syllogism inference. (Contributed by NM, 9-Apr-2005.) |
| ⊢ (𝜑 → 𝜒) & ⊢ ((𝜓 ∧ (𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ ((𝜓 ∧ (𝜑 ∧ 𝜃)) → 𝜏) | ||
| Theorem | sylanr2 689 | A syllogism inference. (Contributed by NM, 9-Apr-2005.) |
| ⊢ (𝜑 → 𝜃) & ⊢ ((𝜓 ∧ (𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ ((𝜓 ∧ (𝜒 ∧ 𝜑)) → 𝜏) | ||
| Theorem | syl6an 690 | A syllogism deduction combined with conjoining antecedents. (Contributed by Alan Sare, 28-Oct-2011.) |
| ⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → (𝜒 → 𝜃)) & ⊢ ((𝜓 ∧ 𝜃) → 𝜏) ⇒ ⊢ (𝜑 → (𝜒 → 𝜏)) | ||
| Theorem | syl2an2r 691 | syl2anr 603 with antecedents in standard conjunction form. (Contributed by Alan Sare, 27-Aug-2016.) (Proof shortened by Wolf Lammen, 28-Mar-2022.) |
| ⊢ (𝜑 → 𝜓) & ⊢ ((𝜑 ∧ 𝜒) → 𝜃) & ⊢ ((𝜓 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜑 ∧ 𝜒) → 𝜏) | ||
| Theorem | syl2an2 692 | syl2an 602 with antecedents in standard conjunction form. (Contributed by Alan Sare, 27-Aug-2016.) |
| ⊢ (𝜑 → 𝜓) & ⊢ ((𝜒 ∧ 𝜑) → 𝜃) & ⊢ ((𝜓 ∧ 𝜃) → 𝜏) ⇒ ⊢ ((𝜒 ∧ 𝜑) → 𝜏) | ||
| Theorem | mpdan 693 | An inference based on modus ponens. (Contributed by NM, 23-May-1999.) (Proof shortened by Wolf Lammen, 22-Nov-2012.) |
| ⊢ (𝜑 → 𝜓) & ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (𝜑 → 𝜒) | ||
| Theorem | mpancom 694 | An inference based on modus ponens with commutation of antecedents. (Contributed by NM, 28-Oct-2003.) (Proof shortened by Wolf Lammen, 7-Apr-2013.) |
| ⊢ (𝜓 → 𝜑) & ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (𝜓 → 𝜒) | ||
| Theorem | mpidan 695 | A deduction which "stacks" a hypothesis. (Contributed by Stanislas Polu, 9-Mar-2020.) (Proof shortened by Wolf Lammen, 28-Mar-2021.) |
| ⊢ (𝜑 → 𝜒) & ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜃) | ||
| Theorem | mpan 696 | An inference based on modus ponens. (Contributed by NM, 30-Aug-1993.) (Proof shortened by Wolf Lammen, 7-Apr-2013.) |
| ⊢ 𝜑 & ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (𝜓 → 𝜒) | ||
| Theorem | mpan2 697 | An inference based on modus ponens. (Contributed by NM, 16-Sep-1993.) (Proof shortened by Wolf Lammen, 19-Nov-2012.) |
| ⊢ 𝜓 & ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (𝜑 → 𝜒) | ||
| Theorem | mp2an 698 | An inference based on modus ponens. (Contributed by NM, 13-Apr-1995.) |
| ⊢ 𝜑 & ⊢ 𝜓 & ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ 𝜒 | ||
| Theorem | mp4an 699 | An inference based on modus ponens. (Contributed by Jeff Madsen, 15-Jun-2010.) |
| ⊢ 𝜑 & ⊢ 𝜓 & ⊢ 𝜒 & ⊢ 𝜃 & ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ 𝜏 | ||
| Theorem | mpan2d 700 | A deduction based on modus ponens. (Contributed by NM, 12-Dec-2004.) |
| ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → 𝜃)) ⇒ ⊢ (𝜑 → (𝜓 → 𝜃)) | ||
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