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Theorem bj-ceqsal 36888
Description: Remove from ceqsal 3518 dependency on ax-ext 2707 (and on df-cleq 2728, df-v 3481, df-clab 2714, df-sb 2064). (Contributed by BJ, 12-Oct-2019.) (Proof modification is discouraged.)
Hypotheses
Ref Expression
bj-ceqsal.1 𝑥𝜓
bj-ceqsal.2 𝐴 ∈ V
bj-ceqsal.3 (𝑥 = 𝐴 → (𝜑𝜓))
Assertion
Ref Expression
bj-ceqsal (∀𝑥(𝑥 = 𝐴𝜑) ↔ 𝜓)
Distinct variable group:   𝑥,𝐴
Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥)

Proof of Theorem bj-ceqsal
StepHypRef Expression
1 bj-ceqsal.2 . 2 𝐴 ∈ V
2 bj-ceqsal.1 . . 3 𝑥𝜓
3 bj-ceqsal.3 . . 3 (𝑥 = 𝐴 → (𝜑𝜓))
42, 3bj-ceqsalgv 36886 . 2 (𝐴 ∈ V → (∀𝑥(𝑥 = 𝐴𝜑) ↔ 𝜓))
51, 4ax-mp 5 1 (∀𝑥(𝑥 = 𝐴𝜑) ↔ 𝜓)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wal 1536   = wceq 1538  wnf 1781  wcel 2107  Vcvv 3479
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1793  ax-4 1807  ax-5 1909  ax-6 1966  ax-7 2006  ax-8 2109  ax-12 2176
This theorem depends on definitions:  df-bi 207  df-an 396  df-3an 1088  df-ex 1778  df-nf 1782  df-clel 2815
This theorem is referenced by:  bj-ceqsalv  36889
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