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Theorem bj-rabeqbid 37755
Description: Version of rabeqbidv 3429 with two disjoint variable conditions removed and the third replaced by a nonfreeness hypothesis. (Contributed by BJ, 27-Apr-2019.)
Hypotheses
Ref Expression
bj-rabeqbid.nf Ⅎ𝑥𝜑
bj-rabeqbid.1 (𝜑 → 𝐴 = 𝐵)
bj-rabeqbid.2 (𝜑 → (𝜓 ↔ 𝜒))
Assertion
Ref Expression
bj-rabeqbid (𝜑 → {𝑥 ∈ 𝐴 ∣ 𝜓} = {𝑥 ∈ 𝐵 ∣ 𝜒})

Proof of Theorem bj-rabeqbid
StepHypRef Expression
1 bj-rabeqbid.nf . . 3 Ⅎ𝑥𝜑
2 bj-rabeqbid.1 . . 3 (𝜑 → 𝐴 = 𝐵)
31, 2rabeqd 3439 . 2 (𝜑 → {𝑥 ∈ 𝐴 ∣ 𝜓} = {𝑥 ∈ 𝐵 ∣ 𝜓})
4 bj-rabeqbid.2 . . 3 (𝜑 → (𝜓 ↔ 𝜒))
51, 4rabbid 3438 . 2 (𝜑 → {𝑥 ∈ 𝐵 ∣ 𝜓} = {𝑥 ∈ 𝐵 ∣ 𝜒})
63, 5eqtrd 2795 1 (𝜑 → {𝑥 ∈ 𝐴 ∣ 𝜓} = {𝑥 ∈ 𝐵 ∣ 𝜒})
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   = wceq 1570  Ⅎwnf 1816  {crab 3412
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-12 2213  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-nf 1817  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-rab 3413
This theorem is used by: (None)
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