Theorem bj-vtoclg1f 37648

Description: Reprove vtoclg1f 3533 from bj-vtoclg1f1 37647. This removes dependency on ax-ext 2734, df-cleq 2754 and df-v 3455. Use bj-vtoclg1fv 37649 instead when sufficient (in particular when 𝑉 is substituted for V). (Contributed by BJ, 14-Sep-2019.) (Proof modification is discouraged.)

Hypotheses

Ref	Expression
bj-vtoclg1f.nf	⊢ Ⅎ𝑥𝜓
bj-vtoclg1f.maj	⊢ (𝑥 = 𝐴 → (𝜑 → 𝜓))
bj-vtoclg1f.min	⊢ 𝜑

Assertion

Ref	Expression
bj-vtoclg1f	⊢ (𝐴 ∈ 𝑉 → 𝜓)

Distinct variable group:   𝑥,𝐴

Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥)   𝑉(𝑥)

Proof of Theorem bj-vtoclg1f

Step	Hyp	Ref	Expression
1		elisset 2844	. 2 ⊢ (𝐴 ∈ 𝑉 → ∃𝑥 𝑥 = 𝐴)
2		bj-vtoclg1f.nf	. . 3 ⊢ Ⅎ𝑥𝜓
3		bj-vtoclg1f.maj	. . 3 ⊢ (𝑥 = 𝐴 → (𝜑 → 𝜓))
4		bj-vtoclg1f.min	. . 3 ⊢ 𝜑
5	2, 3, 4	bj-exlimmpi 37642	. 2 ⊢ (∃𝑥 𝑥 = 𝐴 → 𝜓)
6	1, 5	syl 18	1 ⊢ (𝐴 ∈ 𝑉 → 𝜓)

This proof depends on syntax axioms:   → wi 4   = wceq 1570  ∃wex 1812  Ⅎwnf 1816   ∈ wcel 2145

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-12 2215

This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-nf 1817  df-sb 2100  df-clab 2741  df-clel 2837

This theorem is used by: (None)